What is the answer to this question i have a screen shot

Concert marketing: The college’s performing arts center wanted to investigate why ticket sales for the upcoming season significa

Vesnalui [34]

Answer- a,b,d!!!! (i believe)

8 0

3 years ago

Critical Thinking: Empirical/Quantitative Skills

aliya0001 [1]

Answer:

1. 0.0910 = 9.10% probability that exactly 180 passengers show up for the flight.

2. 0.4522 = 45.22% probability that at most 180 passengers show up for the flight.

3. 0.5478 = 54.78% probability that more than 180 passengers show up for the flight.

Step-by-step explanation:

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

Can be approximated to a normal distribution, using the expected value and the standard deviation.

The expected value of the binomial distribution is:

$E(X) = np$

The standard deviation of the binomial distribution is:

$\sqrt{V(X)} = \sqrt{np(1-p)}$

Normal probability distribution

Problems of normally distributed distributions can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

When we are approximating a binomial distribution to a normal one, we have that $\mu = E(X)$ , $\sigma = \sqrt{V(X)}$ .

Assume that there is a 0.905 probability that a passenger with a ticket will show up for the flight.

This means that $p = 0.905$

Also assume that the airline sells 200 tickets

This means that $n = 200$

Question 1:

Exactly, so we can use the P(X = x) formula, to find P(X = 180).

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 180) = C_{200,180}.(0.905)^{180}.(0.095)^{20} = 0.0910$

0.0910 = 9.10% probability that exactly 180 passengers show up for the flight.

2. When 200 tickets are sold, calculate the probability that at most 180 passengers show up for the flight.

Now we have to use the approximation.

Mean and standard deviation:

$\mu = E(X) = np = 200*0.905 = 181$

$\sigma = \sqrt{V(X)} = \sqrt{np(1-p)} = \sqrt{200*0.905*0.095} = 4.15$

Using continuity correction, this is $P(X \leq 180 + 0.5) = P(X \leq 180.5)$ , which is the p-value of Z when X = 180.5. Thus

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{180.5 - 181}{4.15}$

$Z = -0.12$

$Z = -0.12$ has a p-value of 0.4522.

0.4522 = 45.22% probability that at most 180 passengers show up for the flight.

3. When 200 tickets are sold, calculate the probability that more than 180 passengers show up for the flight.

Complementary event with at most 180 passengers showing up, which means that the sum of these probabilities is 1. So

$p + 0.4522 = 1$

$p = 1 - 0.4522 = 0.5478$

0.5478 = 54.78% probability that more than 180 passengers show up for the flight.

4 0

3 years ago

Can someone help me with this??

dusya [7]

Answer:

Carlos and Pamela drove 120 miles on the first day, 240 miles on the second day, and 290 miles on the third day.

Step-by-step explanation:

Let x be the number of miles driven on the first day.

Then they drove twice as many miles, or 2x on the second day

and 50 miles more than the second day's, so 2x + 50

The total is 650 across all three days, so we'll take the sum.

x + 2x + (2x + 50) = 650

Combine like terms on the left

5x + 50 = 650

Subtract 50 on both sides

5x = 600

Divide by 5 on both sides

x = 120

Check work:

120 + 2(120) + 2(120) + 50 = 650

120 + 240 + 240 + 50 = 650

600 + 50 = 650

650 = 650

So they drove 120 miles on the first day

2*120 = 240 miles on the second day

and 2*120 + 50 = 240 + 50 = 290 miles on the third day

4 0

3 years ago

Pls help me with 19,20 pls thx and show me how u did it

Anastasy [175]

For number 19:
"at least 150" means either 150 ≤ ? or ? ≥ 150

plus 3 so +3x

The answer would be 150 ≤ 100 + 3x

Number 20:

A is at -2.5. The inverse is the opposite so 2.5

7 0

3 years ago

625/1296 simplified fraction

qwelly [4]

Answer:

163/324

Step-by-step explanation:

6 0

3 years ago

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