Question
Cable company A charges $45 a month for cable plus a $18 installation fee. Cable B charges $39 a month for cable plus a $30 fee for installation. Which inequality can be used to find out when the monthly cost for Cable company A is less than Cable company B?
a)39x+30<45x+18
b) 45x+18>39x+30
c) 45x+18<39x+30
d)39x+18<45x+30
Answer:
c) 45x+18<39x+30
Step-by-step explanation:
Step 1
We have to find the Algebraic expressions for the cable companies
Cable company A charges $45 a month for cable plus a $18 installation fee.
Let the number of months be represented as x
Hence, this is represented as:
$45 × x + $18
= 45x + 18
Cable B charges $39 a month for cable plus a $30 fee for installation.
Let the number of months be represented as x
Hence, this is represented as:
$39 × x + $30
= 39x + 30
The inequality that can be used to find out when the monthly cost for Cable company A is less than Cable company B?
= Cable company A < Cable company B
= 45x + 18 < 39x + 30
Therefore option c is correct
Answer:(2 1/2, -9)
Step-by-step explanation:
Answer: There can be more than one zero
An x-intercept is located at the point on the function where the value of x is 0.
theres a lot lol. can you be more specific if these are wrong?
Step-by-step explanation:
Answer:
y = - 
x + 3
Step-by-step explanation:
The equation of a line in slope- intercept form is
y = mx + c ( m is the slope and c the y- intercept )
Calculate m using the slope formula
m = (y₂ - y₁ ) / (x₂ - x₁ )
with (x₁, y₁ ) = (3, 2) and (x₂, y₂ ) = (- 9, 6)
m = 
= 
= - , hence
y = - x + c ← is the partial equation
To find c substitute either of the 2 points into the partial equation
Using (- 9, 6), then
6 = 3 + c ⇒ c = 6 - 3 = 3
y = - x + 3 ← in slope- intercept form
15% of 30 = 4.5
30% of 45= 13.5
60% of 7= 4.2
23% of 20= 4.6
