Answer:
<u>15%</u>
Step-by-step explanation:
The reason for this is simply because if you take 40 and 6, turn it into a fraction, then turn it into a percentage, it turns out to be 15%
THis equals the number of permutations of 4 from 6.
= 6P4 = 6! / (6 - 4)! = 6! / 2! = 720/2 = 360 answer
Answer:
X : ___ 0 ____ 1 _____ 2 ______ 3
P(X) : _ 6/15 __ 5/15__ 3/15 ____ 1/15
Step-by-step explanation:
From the data, to produce a probability distribution for the data :
X : number of times blood is drawn ;
P(x) : probability that blood is drawn at X times
Hence, the probability distribution table for the data Given goes thus :
X : ___ 0 ____ 1 _____ 2 ______ 3
P(X) : _ 6/15 __ 5/15__ 3/15 ____ 1/15
Probability that blood is drawn 0 times = 6/15
Probability that blood is drawn 1 time = 5/15
Probability that blood is drawn 2 times = 3/15
Probability that blood is drawn 3 times = 1/15
(6/15 + 5/15 + 3/15 + 1/15) = 1
I believe the answer would be 2 23/42. Sorry, if I am wrong with this answer. Sorry, i also mean the answer should be actually 1 3/7
Answer:
Step-by-step explanation:
Let 
Subbing in:

a = 9, b = -2, c = -7
The product of a and c is the aboslute value of -63, so a*c = 63. We need 2 factors of 63 that will add to give us -2. The factors of 63 are {1, 63}, (3, 21}, {7, 9}. It looks like the combination of -9 and +7 will work because -9 + 7 = -2. Plug in accordingly:

Group together in groups of 2:

Now factor out what's common within each set of parenthesis:

We know this combination "works" because the terms inside the parenthesis are identical. We can now factor those out and what's left goes together in another set of parenthesis:

Remember that 
so we sub back in and continue to factor. This was originally a fourth degree polynomial; that means we have 4 solutions.

The first two solutions are found withing the first set of parenthesis and the second two are found in other set of parenthesis. Factoring
gives us that x = 1 and -1. The other set is a bit more tricky. If
then
and

You cannot take the square root of a negative number without allowing for the imaginary component, i, so we do that:
±
which will simplify down to
±
Those are the 4 solutions to the quartic equation.