m∠BAC = 27°
Solution:
ABCD is a quadrilateral.
AB and CD are parallel lines.
Given m∠BCD = 54°
AC bisect ∠BCD.
m∠DCA + m∠CAB = m∠BCD
m∠DCA + m∠DCA = 54° (since ∠ACB = ∠DCA)
2 m∠DCA = 54°
Divide by 2 on both sides, we get
m∠DCA = 27°
AB and CD are parallel lines and AC is the transversal.
<em>If two parallel lines cut by a transversal, then the alternate interior angles are equal.</em>
m∠BAC = m∠DCA
m∠BAC = 27°
Hence m∠BAC = 27°.
She drank about 0.60 quarts
hope this helps!
Y = 4x + 1....slope here is 4. A parallel line will have the same slope
y = mx + b
slope(m) = 4
(3,9)...x = 3 and y = 9
now we sub and find b, the y int
9 = 4(3) + b
9 = 12 + b
9 - 12 = b
-3 = b
so ur parallel equation is : y = 4x - 3
Answer:
3/7
Step-by-step explanation:
The prime numbers that lie between 1 and 21 are 2,3,5,7,11,13,17, and 19. These 8 balls, plus the 10-ball comes to a total of 9 balls that could be picked out of the 21. Therefore, the probability of picking one of these balls is 9/21 or 3/7
Answer:
I think this is the answer
Step-by-step explanation:
angle 3
angle 4
angle 2 is 49
angle 1
