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3 years ago

Besties helpppp please FASTTT

Mathematics

1 answer:

gizmo_the_mogwai [7]3 years ago

4 0

Answer:

180

Step-by-step explanation:

area of a trapezoid = $\frac{a+b}{2}h$

where a = base 1

b = base 2

and h = height

This is what we are given

base 1 = 23

base 2 = 37

and height = 6

That being said we plug in the given values into the formula

$A=\frac{37+23}{2} 6\\23+37=60\\\frac{60}{2} =30\\30*6=180$

Hence the area of the trapezoid is 180 square feet

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What is the correct answer to this

igomit [66]

Answer:

Perimeter = 9700 cm

Step-by-step explanation:

Dimensions of sides are;

12, 2x, 12, 5, 5, circumference of semi circle

Now, the semi circle has a radius of 7. Thus, the diameter = 7 × 2 = 14

We see that x is the diameter. Thus, x = 14

Thus; base of trapezium that is 2x = 2 × 14 = 28

Also, circumference of semi circle = 2πr = 2π × 7 = 44

Thus;

Perimeter of shape = 12 + 2(14) + 12 + 5 + 5 + 44

Perimeter = 97 m

Converting to cm, we multiply by 100 to get;

Perimeter = 97 × 100 cm

Perimeter = 9700 cm

8 0

3 years ago

Please help!! I only have 30 minutes left!! Given that x and y are positive integers and (x·2)+x(2^2)+(y·2^3)+(y·2^4)=42, what i

Viktor [21]

Answer:

xy = 3

Step-by-step explanation:

The expression to be evaluated is:

$2\cdot x +4\cdot x + 8\cdot y + 16\cdot y = 42$

$6\cdot x + 24\cdot y = 42$

By some algebraic handling:

$6\cdot (x + 4\cdot y) = 42$

Where:

$x+4\cdot y = 7$

There is one possible solution:

x = 3, y = 1

And consequently,

xy = 3

4 0

3 years ago

graph of a cubic polynomial that falls to the left and rises to the right with x intercepts negative 3, negative 2, and 2 Which

Maksim231197 [3]

Answer:

i would say f(x) = (x-2)(x-3)(x+2) but i could be wrong its a confusing question the way it's worded

Step-by-step explanation:

and i'm sorry if i was wrong

8 0

4 years ago

Read 2 more answers

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Solnce55 [7]

Answer:

Try 9 x j(2 + 5)

4 0

3 years ago

Read 2 more answers

Suppose A,B and C are 2 ×2 matrices , E,F and G are 3 × 3 matrices, H and K are 2×3 matrices and L and M are 3×2 matrices. For e

Alekssandra [29.7K]

Answer:

a) 2x2 b)3x3 c) Not possible d) 2x3 e) 3x2 f) 3x3 g)Not possible h)3x2

Step-by-step explanation:

-> we can only add matrices with same size

-> we can only multiply when columns of first equal to rows of second

-> nxm multiplied by pxq gives nxq eg 3x2 mul 2x2 gives 3x2

-> addition and mul by const number dont change the size

So considering the above facts :-

a) AB+C = [(2x2)(2X2)]+(2x2)=(2x2)+(2x2)=2x2

b) 3GF =3[(3x3)(3x3)]=3(3x3)=3x3

c)CK+B= [(2x2)(2x3)]+(2x2)=(2x3)+(2x2) which is not possible (see point 1)

d)CK+H =as CK is (2x3) so (2x3)+(2x3)=(2x3)

e)EMC=[(3x3)(3x2)](2x2)=(3x2)(2x2)=3x3

f)GLH=[(3x3)(3x2)](2x3)=(3x2)(2x3)=3x3

g)HLG=[(2x3)(3x2)](3x3)=(2x2)(3x3)= not possible(see point 2)

h)2EL+5MB=2[(3x3)(3x2)]+5[(3x2)(2x2)]=(3x2)+(3x2)=3x2

8 0

3 years ago