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Firdavs [7]
3 years ago
8

Does anyone know what this equation is? I'm pretty sure the first part is surface area

Mathematics
1 answer:
LekaFEV [45]3 years ago
6 0
There is so equation showed

sorry for incovinonce
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Which statement about the following sequence is true? -10, -3, -10, -3, -10, ... Question 3 options: It is arithmetic. It is geo
Novosadov [1.4K]

Answer:

What is the value of a2 in the sequence?

2, 5, 10, 17, ... is 2

What is the value of a3 in the sequence?

−4, −2, −1/2, −1/4, ... is ​ −1/2 ​

Which answer describes the type of sequence?

3, 9, 15, 21, ...is arithmetic with d=6

Which answer describes the type of sequence?

4, 9, 13, 22, ...

is neither arithmetic nor geometric

Which answer describes the type of sequence?

200, 40, 8, 1.6, ...

is geometric with q=1/5

 Have fun

7 0
2 years ago
Read 2 more answers
How often should you study
GalinKa [24]
I study like 2-3 hours every day, and 3 hours playing xbox lol. But yeah, what are you currently studying?
5 0
3 years ago
Let f be the function defined as follows:
katen-ka-za [31]

With f defined by

f(x)=\begin{cases}|x-1|+2&\text{for }x

in order for it to be continuous at x=c, we require

\displaystyle\lim_{x\to c^-}f(x)=\lim_{x\to c^+}f(x)=f(c)

(i) If a=2 and b=3, then f(1)=2(1)^2+3(1)=5 and

\displaystyle\lim_{x\to1^-}f(x)=\lim_{x\to1}|x-1|+2=2

\displaystyle\lim_{x\to1^+}f(x)=\lim_{x\to1}2x^2+3x=5

The limits don't match, so f is not continuous at x=1 under these conditions.

(ii) To establish continuity at x=1, we'd need the limit as x\to1 from the right to be equal to the limit from the left, or

\displaystyle\lim_{x\to1}ax^2+bx=\lim_{x\to1}|x-1|+2\iff a+b=2

(iii) We have f(2)=0 and

\displaystyle\lim_{x\to2^-}f(x)=\lim_{x\to2}ax^2+bx=4a+2b

\displaystyle\lim_{x\to2^+}f(x)=\lim_{x\to2}5x-10=0

For f to be continuous at x=2, then, we'd need to have

4a+2b=0

(iv) Taking both requirements from parts (ii) and (iii), we solve for a,b:

\begin{cases}a+b=2\\4a+2b=0\end{cases}\implies a=-2,b=4

I've attached a plot that confirms this is correct.

7 0
3 years ago
What is the slope of the line that passes through the points (−4,8) and (-14, 8) ? answer inn simplest form
lidiya [134]

Answer:

the answer is 0

Step-by-step explanation:

we have slope of a line passing through two given points is

slope = rise / run

there is no rise in here i.e. 8-8= 0

there fore the slope = 0/ run = 0

other formula

slope =

\frac{x2 - x1}{y2 - y1}

=

\frac{8 - 8}{ - 14 + 4}

=0/-10

=0

5 0
2 years ago
Write into a single logarithm log b (X+1)+ log b (X-8)
ElenaW [278]
To solve, use properties of logs, specifically log(u)+log(v)=log(uv). This makes your equation logb(x+1)+logb(x-8)=logb((x+1)(x-8)), which can be made into logb(x^2-7x-8) by expanding the factored form.
3 0
2 years ago
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