Answer:
The answer in the procedure
Step-by-step explanation:
Let
A1 ------> the area of the first square painting
A2 ----> the area of the second square painting
D -----> the difference of the areas
we have


case 1) The area of the second square painting is greater than the area of the first square painting
The difference of the area of the paintings is equal to subtract the area of the first square painting from the area of the second square painting
D=A2-A1


case 2) The area of the first square painting is greater than the area of the second square painting
The difference of the area of the paintings is equal to subtract the area of the second square painting from the area of the first square painting
D=A1-A2


Solve the inequality 1.6-(3-2y)<5.
1. Rewrite this inequality without brackets:
1.6-3+2y<5.
2. Separate terms with y and without y in different sides of inequality:
2y<5-1.6+3,
2y<6.4.
3. Divide this inequality by 2:
y<3.2
4. The greatest integer that satisfies this inequality is 3.
Answer: 3.
The three points give you three equations, which you can solve by your favorite method.
.. 0m +0n +b = 6
.. 1m +0n +b = -3
.. 0m +2n +b = 5
(m, n, b) = (-9, -1/2, 6)
so the equation of the plane can be written as
.. z = -9x -1/2y +6
_____
In standard form, this would be
.. 18x +y +2z = 12
Answer:
no they are not because 11, 14 is the only one that has a vertices
Step-by-step explanation: