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3 years ago

7

There are 14 horses and 56 camels at the stable. What fraction of animals in the stable are horses?

2 answers:

Harlamova29_29 [7]3 years ago

8 0

Step-by-step explanation: Since there are 14 horses, 14 - 6 -5 = 3 are black.

a) 3 out of 14 are black, so probability is 3/14 chosen horse will be black

b) 1 - 3/14 = 11/14 probability will not be black

c) 6 are brown and 3 are black, so 9/14 probability chosen horse will be either.

aleksandrvk [35]3 years ago

5 0

Answer:

1/4

Step-by-step explanation:

if you do it on a calculator it comes out to 0.25 which equals 1/4

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Find all of the equilibrium solutions. Enter your answer as a list of ordered pairs (R,W), where R is the number of rabbits and

zloy xaker [14]

Answer:

$(0,0)$ $(4000,0)$ and $(500,79)$

Step-by-step explanation:

Given

See attachment for complete question

Required

Determine the equilibrium solutions

We have:

$\frac{dR}{dt} = 0.09R(1 - 0.00025R) - 0.001RW$

$\frac{dW}{dt} = -0.02W + 0.00004RW$

To solve this, we first equate $\frac{dR}{dt}$ and $\frac{dW}{dt}$ to 0.

So, we have:

$0.09R(1 - 0.00025R) - 0.001RW = 0$

$-0.02W + 0.00004RW = 0$

Factor out R in $0.09R(1 - 0.00025R) - 0.001RW = 0$

$R(0.09(1 - 0.00025R) - 0.001W) = 0$

Split

$R = 0$ or $0.09(1 - 0.00025R) - 0.001W = 0$

$R = 0$ or $0.09 - 2.25 * 10^{-5}R - 0.001W = 0$

Factor out W in $-0.02W + 0.00004RW = 0$

$W(-0.02 + 0.00004R) = 0$

Split

$W = 0$ or $-0.02 + 0.00004R = 0$

Solve for R

$-0.02 + 0.00004R = 0$

$0.00004R = 0.02$

Make R the subject

$R = \frac{0.02}{0.00004}$

$R = 500$

When $R = 500$ , we have:

$0.09 - 2.25 * 10^{-5}R - 0.001W = 0$

$0.09 -2.25 * 10^{-5} * 500 - 0.001W = 0$

$0.09 -0.01125 - 0.001W = 0$

$0.07875 - 0.001W = 0$

Collect like terms

$- 0.001W = -0.07875$

Solve for W

$W = \frac{-0.07875}{ - 0.001}$

$W = 78.75$

$W \approx 79$

$(R,W) \to (500,79)$

When $W = 0$ , we have:

$0.09 - 2.25 * 10^{-5}R - 0.001W = 0$

$0.09 - 2.25 * 10^{-5}R - 0.001*0 = 0$

$0.09 - 2.25 * 10^{-5}R = 0$

Collect like terms

$- 2.25 * 10^{-5}R = -0.09$

Solve for R

$R = \frac{-0.09}{- 2.25 * 10^{-5}}$

$R = 4000$

So, we have:

$(R,W) \to (4000,0)$

When $R =0$ , we have:

$-0.02W + 0.00004RW = 0$

$-0.02W + 0.00004W*0 = 0$

$-0.02W + 0 = 0$

$-0.02W = 0$

$W=0$

So, we have:

$(R,W) \to (0,0)$

Hence, the points of equilibrium are:

$(0,0)$ $(4000,0)$ and $(500,79)$

4 0

3 years ago

Find the solution of y=x-3

PtichkaEL [24]

Answer:

x=3

Step-by-step explanation:

0 = x -3

-x = -3

change the sign to positive so x= 3

8 0

3 years ago

2. Solve the below proportion. Please help me.

antoniya [11.8K]

32 3t try add it all up maybe it work but that's the answer

4 0

2 years ago

Read 2 more answers

Should you use Sine, Cosine, or Tangent to solve the following problem

olga55 [171]

tangent

Step-by-step explanation:

because it gave u an angel and and adjacent so your x is the opposite so sin20=x÷17 just use your calculator u will find the ans

8 0

3 years ago

Which expression is equivalent to (265x^16)^1/4?

inn [45]

Answer:

265x/8

I have no idea if this is correct, sorry if it isn't.

6 0

3 years ago