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2 years ago

A right triangle has side lengths d, e and f as shown below use these lengths to find cos x, tan x and sin x

Mathematics

2 answers:

kvasek [131]2 years ago

6 0

Answer:

To solve for the trigonometric functions of x, we need to recall the ratios they represent as shown below.

sin x = O/H

cos x = A/H

tan x = O/A

where O stands for opposite, A for adjacent, and H for hypotenuse. So, for example, the sine of x is equal to the side opposite of angle x over the hypotenuse. The same goes for cosine and tangent. Using the diagram attached, we have the expressions of the trigonometric functions as shown below.

sin x = f/d

cos x = e/d

tan x = f/e

Step-by-step explanation:

Ilya [14]2 years ago

5 0

Answer:

Step-by-step explanation:

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Put brackets in the calculation below to make it correct.<br><br> 15 - 4 x 2 + 1 = 3

bagirrra123 [75]

If you put brackets around (2+1), your method of working is:
1) 15-4*(2+1)=3
2) 15-4*3=3
3) 15-12=3
You don't need any more brackets, as the BIDMAS (brackets, Indices, division, multiplication, addition, subtraction) rule does the rest of the job for you.
The answer is therefore: 15-4*(2+1)=3

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A semi-circle with a diameter of 6 cm sits on top of an isosceles trapezoid. Find the area of the entire figure.

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Answer:

Step-by-step explanation:

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2 years ago

John purchased 1/4 lbs of hamburger for $0.75. How much did the hamburger cost per pound?

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3 years ago

Suppose that, for a particular social networking company, the annual revenue from rich media advertisements, in millions of doll

Juli2301 [7.4K]

Answer:

a. Revenue of the company at the beginning of 2010 is 75 million dollar (loss)

b. Rate at which the revenue changing in the year 2010 is 76 million dollar per year ( decreasing)

Step-by-step explanation:

For part a,

Given that x is the number of years at the beginning of 2007.

Therefore, $x=0$ for year 2007.

Hence at the year 2010 value of x will be $x=3$ .

Substitute the value of x=3 in R(x),

$R\left(x\right)=-x^{4}+8x^{3}-38x^{2}+44x$

$R\left(x\right)=-\left(81\right)+8\left(27\right)-38\left(9\right)+132$

$R\left(x\right)=-81+216-342+132$

$R\left(x\right)=-75$

Negative sign indicates that there is loss of revenue at the start of the year 2010

Therefore, there is loss of revenue at the beginning of 2010 which is 75 million dollar.

For part b,

To calculate rate, differentiate the given function with respect to x.

$\dfrac{d}{dx}R\left(x\right)=\dfrac{d}{dx}\left (-\left(x\right)^{4}+8\left(x\right)^{3}-38\left(x\right)^{2}+44\left(x\right)\right)$

Applying sum and difference rule of derivative,

$\dfrac{d}{dx}R\left(x\right)=-\dfrac{d}{dx}\left(x^4\right)+\dfrac{d}{dx}\left(8x^3\right)-\dfrac{d}{dx}\left(38x^2\right)+\dfrac{d}{dx}\left(44x\right)$

Applying constant multiple rule of derivative,

$\dfrac{d}{dx}R\left(x\right)=-\dfrac{d}{dx}\left(x^4\right)+8\dfrac{d}{dx}\left(x^3\right)-38\dfrac{d}{dx}\left(x^2\right)+44\dfrac{d}{dx}\left(x\right)$

Applying power rule of derivative,

$\dfrac{d}{dx}R\left(x\right)=-\left(4x^{4-1}\right)+8\left(3x^{3-1}\right)-38\left(2x^{2-1}\right)+44\left(1x^{1-1}\right)$

$\dfrac{d}{dx}R\left(x\right)=-4\left(x^{3}\right)+8\left(3x^{2}\right)-38\left(2x^{1}\right)+44$

$\dfrac{d}{dx}R\left(x\right)=-4x^3+24x^2-76x+44$

Substituting the value x=3,

$\dfrac{d}{dx}R\left(x\right)=-4\left(3\right)^3+24\left(3\right)^2-76\left(3\right)+44$

$\dfrac{d}{dx}R\left(x\right)=-4\left(27\right)+24\left(9\right)-76\left(3\right)+44$

$\dfrac{d}{dx}R\left(x\right)=-108+216-228+44$

$\dfrac{d}{dx}R\left(x\right)=-76$

Negative sign indicates that rate is decreasing.

Rate at which the revenue is changing in the year 2010 is 76 million dollar per year.

8 0

2 years ago