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astraxan [27]
2 years ago
9

What is the mean? -1 -1 -4 -5 -4 -4 -7 -8

Mathematics
1 answer:
vlabodo [156]2 years ago
3 0

Answer:

Nagative numbers(numbers smaller than 0)

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What value of c is the rational expression below equal to zero? x-4/x-6
RSB [31]

Answer: x=4

Steps: (I am assuming your question has a typo in it and by "c" you meant "x")

The rational expression equals zero

\frac{x-4}{x-6}=0

only when the numerator equals 0 (the denominator cannot ever be zero):

x-4 = 0 \\x = 4

and that happens only for x=4


3 0
3 years ago
Given the function, f(x) = | x-2 | + 1
Genrish500 [490]
What do you need to do with this?
8 0
2 years ago
Suppose 60% of American adults believe Martha Stewart is guilty of obstruction of justice and fraud related to insider trading.
Ierofanga [76]

Answer:

Since the sample size is large enough (n>30) and the probability of success is near to 0.5, and we have that n\hat p = 60>10 and n(1-\hat p) = 40>10 we can assume that the distribution for \hat p is normal

The population proportion have the following distribution  

\hat p \sim N(\hat p,\sqrt{\frac{\hat p(1-\hat p)}{n}})  

The mean is given by:

\mu_p = 0.6

\sigma_p = \sqrt{\frac{0.6*(1-0.6)}{100}}=0.04899

So then we can conclude that the best answer would be:

c. approximately Normal, with mean 0.6 and standard error 0.04899

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".  

The margin of error is the range of values below and above the sample statistic in a confidence interval.  

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".  

p represent the real population proportion of interest

\hat p represent the estimated proportion for the sample

n is the sample size required (variable of interest)

Solution to the problem

Since the sample size is large enough (n>30) and the probability of success is near to 0.5, and we have that n\hat p = 60>10 and n(1-\hat p) = 40>10 we can assume that the distribution for \hat p is normal

The population proportion have the following distribution  

\hat p \sim N(\hat p,\sqrt{\frac{\hat p(1-\hat p)}{n}})  

The mean is given by:

\mu_p = 0.6

\sigma_p = \sqrt{\frac{0.6*(1-0.6)}{100}}=0.04899

So then we can conclude that the best answer would be:

c. approximately Normal, with mean 0.6 and standard error 0.04899

8 0
3 years ago
Simplify the expression. –16 • 1/8 • 4 + 32 ÷ 2
DanielleElmas [232]

Answer:

8

Step-by-step explanation:

–16 • 1/8 • 4 + 32 ÷ 2

Using PEMDAS, we multiply and divide from left to right since there are no parentheses or exponents.

-2 • 4 + 32 ÷ 2

-8 +32 ÷ 2

-8 + 16

Now we add and subtract from left to right

8

5 0
3 years ago
| 3. Write the decimal equiva
EastWind [94]

Answer:

a. 0.19

e. 0.03

Step-by-step explanation:

move the decimal place of the percents back 2 places

5 0
2 years ago
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