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yanalaym [24]
3 years ago
12

Find the 29th term in the arithmetic sequence: -13, -6, 1, 8........

Mathematics
1 answer:
alexandr1967 [171]3 years ago
8 0

Answer:

183

Step-by-step explanation:

a₁ = -13

common difference = a₂ - a₁

                                 = (-6) - (-13)

                                = -6 + 13

                               d = 7

nth term = a₁ + (n - 1)d

29th term = -13 + 28 * 7

               = -13 + 196

               = 183

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shira was riding the screamer when it broke down. her seat was 53 jorizontal feet from the central support pole. What was her se
ki77a [65]

Answer:

The possible solutions are 58 degree, 122 degrees, 302 degrees and 238 degrees

Step-by-step explanation:

Please see the attachment

From the figure, it is evident that

cos AOB = OB/OA = 53/100 = 0.53

Thus, cos-1 (0.53) = 58 degrees

AOB = 58 degree

Also, there are can be other values depending on the quadrants

COB = 180 -58 = 122 degrees

FOB = 360 -58 = 302 degrees

EOB = 180 + 58 = 238 degrees

5 0
3 years ago
Araceli uses 9.6 pints of blue paint and white paint to paint her bedroom walls. Three fourths of this amount is blue paint , an
Soloha48 [4]

Answer:

2.4 pints

Step-by-step explanation:

Araceli uses 9.6 pints of blue paint and white paints, that means the total volume of paint is 9.6 pints

If Three fourths of this amount is blue paint ,

Then  \frac{3}{4} X 9.6=7.2 pints

7.2 pints of blue paint was used.

We want to find out how much white paint was used by Araceli

Volume of Blue Paint+Volume of White Paint=Total Volume of Paint

7.2+Volume of White Paint=9.6

Volume of White Paint=9.6-7.2=2.4 pints

6 0
3 years ago
What are the factors of 2x + 3x - 54? Select two options
tiny-mole [99]

Answer:

The answer: The factors are (2x-9) and (x+6).

The Problem:

Factor 2x^2+3x-54

Step-by-step explanation:

So I'm going to do trial factors using the choices to aid me.

Factored form for this problem if it exist will be in the form:

(mx+n)(kx+p).

In general this is what it would look like if we factored any quadratic in terms of x (given the quadratic is not prime but technically you could factor even over the complex numbers).

Let's look at:

(mx+n)(kx+p)

We want to choose k \text{ and } m such that when you multiply them you get 2.  Well those would have to be 2 and 1.

(2x+n)(x+p)

we want to choose n \text{ and } p such that when you multiply them you get -54. Based on the choices we want to get with -9 and 6, or 9 and -6. We don't know the order we want to choose it in either.

For example which of these would work:

(2x-6)(x+9)

(2x+6)(x-9)

(2x-9)(x+6)

(2x+9)(x-6)

We are going to consider only the outer and inner of FOIL since we already know the first times the first is 2x^2 and the last times the last is -54.

Let's test the first one:

(2x-6)(x+9)

Outer:  2x(9)=18x

Inner: -6(x)=-6x

------------------------ADD!

18x-6x=12x

The first choice did not give us the middle term 3x.

Trying the second one would give us the opposite since they are in the same form as previous just the + and - are switched.

Let's look at the third one:

(2x-9)(x+6)

Outer: 2x(6)=12x

Inner: -9(x)=-9x

--------------------------ADD!

12x-9x=3x

This is the winner.

The answer: The factors are (2x-9) and (x+6).

7 0
3 years ago
Read 2 more answers
1/2(16X + 10Y) – 10X – 7Y
Illusion [34]

Answer:

the answer is −2⋅(x+y)

5 0
3 years ago
Write a function with the following characteristics: 1.A vertical asymptote at x = 3 A horizontal asymptote at y = 2 An x-interc
elena-14-01-66 [18.8K]

1. The vertical asymptote requires the denominator have a zero at that location. The x-intercept requires the numerator have a zero at that location. The horizontal asymptote amounts to a multiplier of the function:

... y = 2(x +5)/(x -3)

2. The vertical asymptote requires the denominator have a zero at that location. The oblique asymptote is an add-on

... y = 1/(x +1) +(x +2)

... y = (x² +3x +3)/(x +1)

7 0
3 years ago
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