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viva [34]
3 years ago
7

PLZ HELP PLZ PLZ PLZ HELP

Mathematics
1 answer:
faust18 [17]3 years ago
5 0

Answer:the diameter is 7

Step-by-step explanation: 21.98 divide by pi is 7 so diameter is 7

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an assembly line worker at Rob's Bicycle factory adds a seat to a bicycle at the rate of 2 seats in 11 minutes. Write a proporti
LuckyWell [14K]
Rate = 2 seats/11 minutes = 2/11  seats/min

Therefore the time required for s seats is
(m \, min) =  \frac{s \, seats}{ \frac{2}{11} \,  \frac{seats}{min} } =  \frac{11s}{2} \, min
That is,
m = (11s)/2 min

When s = 16, obtain
m =  \frac{11(16)}{2} = 88 \, min

When s = 19, obtain
m =  \frac{11(19)}{2} = 104.5 \, min

Answers:
m = \frac{11s}{2}
When s = 16, m = 88 min
When s = 19,  m = 104.5 min


3 0
3 years ago
In the first half of a basketball game, a player scored 9 points on free throws and then scored a number of 2-point shots. In th
irinina [24]
I had this same question yesterday it was c 2x+3x+9x
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3 years ago
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Rasek [7]

Answer:

find f(5) and g(5) then divide f(5) by g(5) i.e f(5)/g(5) Answer will be 25/6

3 0
3 years ago
a statistics professor finds that when he schedules an office hour at the 10:30a, time slot, an average of three students arrive
Veseljchak [2.6K]

Answer:

The probability that in a randomly selected office hour in the 10:30 am time slot exactly two students will arrive is 0.2241.

Step-by-step explanation:

Let <em>X</em> = number of students arriving at the 10:30 AM time slot.

The average number of students arriving at the 10:30 AM time slot is, <em>λ</em> = 3.

A random variable representing the occurrence of events in a fixed interval of time is known as Poisson random variables. For example, the number of customers visiting the bank in an hour or the number of typographical error is a book every 10 pages.

The random variable <em>X</em> is also a Poisson random variable because it represents the fixed number of students arriving at the 10:30 AM time slot.

The random variable <em>X</em> follows a Poisson distribution with parameter <em>λ</em> = 3.

The probability mass function of <em>X</em> is given by:

P(X=x)=\frac{e^{-\lambda}\lambda^{x}}{x!};\ x=0,1,2,3...,\ \lambda>0

Compute the probability of <em>X</em> = 2 as follows:

P(X=2)=\frac{e^{-3}3^{2}}{2!}=\frac{0.0498\times 9}{2}=0.2241

Thus, the probability that in a randomly selected office hour in the 10:30 am time slot exactly two students will arrive is 0.2241.

6 0
3 years ago
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nadezda [96]

Answer:D 2 1/7

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8 0
3 years ago
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