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Gnom [1K]
2 years ago
12

7th Grade Math (Please help me with this question I'm confused with this one)

Mathematics
1 answer:
Vlad [161]2 years ago
6 0

Answer:

To subtract a number from another number, the sign of the number (which is to be subtracted) should be changed and then this number with the changed sign, should be added to the first number

Step-by-step explanation:

(i) Evaluate (+6) – (+2)

= (+6) + (-2) (charging the sign of the number to be subtracted and then adding)

On subtracting smaller number 2 from bigger number 6; we get 6 – 2 = 4

Since, the sign of bigger number is + (positive)

= +4 or 4

Therefore, (+6) – (+2) = 4

(ii) Evaluate (+5) – (-3)

= (+5) + (+3) (charging the sign of the number to be subtracted and then adding)

We know, to add a positive (+ ve) number to a positive (+ ve) number, the numbers should be added and positive sign should be attached to the sum obtained.

= +8

Therefore, (+5) – (-3) = 8

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Tell me all the linking verbs
Firlakuza [10]

Answer:

Linking Verbs

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3 0
3 years ago
A man drove his car a distance of 260 miles in 4 hours. If continuing at this rate is possible, he will travel ____ miles in 8 h
spayn [35]

Answer:

520 miles

Step-by-step explanation:

since 4 is half of 8, you just multiply 260 by 2.

4 0
3 years ago
Read 2 more answers
A huge ice glacier in the Himalayas initially covered an area of 454545 square kilometers. Because of changing weather patterns,
guajiro [1.7K]

We have been given that a huge ice glacier in the Himalayas initially covered an area of 45 square kilo-meters. The relationship between A, the area of the glacier in square kilo-meters, and t, the number of years the glacier has been melting, is modeled by the equation A=45e^{-0.05t}.

To find the time it will take for the area of the glacier to decrease to 15 square kilo-meters, we will equate A=15 and solve for t as:

15=45e^{-0.05t}

\frac{15}{45}=\frac{45e^{-0.05t}}{45}

\frac{1}{3}=e^{-0.05t}

Now we will switch sides:

e^{-0.05t}=\frac{1}{3}

Let us take natural log on both sides of equation.

\text{ln}(e^{-0.05t})=\text{ln}(\frac{1}{3})

Using natural log property \text{ln}(a^b)=b\cdot \text{ln}(a), we will get:

-0.05t\cdot \text{ln}(e)=\text{ln}(\frac{1}{3})

-0.05t\cdot (1)=\text{ln}(\frac{1}{3})

-0.05t=\text{ln}(\frac{1}{3})

t=\frac{\text{ln}(\frac{1}{3})}{-0.05}

t=\frac{\text{ln}(\frac{1}{3})\cdot 100}{-0.05\cdot 100}

t=\frac{\text{ln}(\frac{1}{3})\cdot 100}{-5}

t=-\text{ln}(\frac{1}{3})\cdot 20

t=-(\text{ln}(1)-\text{ln}(3))\cdot 20

t=-(0-\text{ln}(3))\cdot 20

t=20\text{ln}(3)

Therefore, it will take 20\text{ln}(3) years for area of the glacier to decrease to 15 square kilo-meters.

6 0
3 years ago
2 Points
Mashcka [7]

Answer:

C

Step-by-step explanation:

Factor: -7x^2 -5x+18

Factor -1 out of 7x^2 -5x +18:

−(7x^2+5x−18)

Factor.

1. 18 is negative, so a negative number multiplied by a postive number.

2. You can't factor 7, so 7x times x.

(7x−9)(x+2)

4 0
4 years ago
What is the range of the function y = 2sin X?
ruslelena [56]

Answer:

Range: [-2, 2] {y | -2 ≤ y ≤ 2}

Step-by-step explanation:

The given function is y = 2sinx

We have to find the range of the given function.

Since at y-axis sine function has the variance between -1 to 1 so range of y = sinx is [-1, 1]

and if the amplitude of sine function is 2 then sine function will vary from -2 to 2 which implies that range of y = 2 sinx will be [-2, 2]

So range of y = 2sinx is [-2, 2]

7 0
2 years ago
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