Question

An airplane travels about 1,500 Km in a straight line between Toronto and Winnipeg. However, the plane must climb to 10,000 m during the first 200 Km, then it must descend 10,000 m during the final 300 Km.
a) How much distance do the climb and descent add to the flight?
b) The airplane averages a speed of 600 km/h. Do climbing and descending 10 000 m add hours, minutes of second to the flight? Explain.

Please help I do not understand how to do this.

Answer 1

Answer:416

Step-by-step explanation: Based on the given problem above, it requires a trigonometric solution. So here it goes:

The climb distance is:200 * Sec [ArcTan [10/200]] = 10√ 401 km

and the decent distance is:300 * Sec [ArcTan [10/300]] = 10√901 km

So add the given results above with 500 km and this will be the additional distance that plane moves through the air.

The answer would be in the unit meters.

((10√401 +10√901−500)∗1000)=416 meters

Hope this is the answer that you are looking for.