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Alla [95]
3 years ago
13

Solve the following systems of equations algebraically. Write your answer in the form of (x, y).

Mathematics
1 answer:
Ne4ueva [31]3 years ago
8 0

Let's solve your system by substitution.
y
=
3
x
+
5
;
y
=
x
+
19

Step: Solve
y
=
3
x
+
5
for y:
y
=
3
x
+
5

Step: Substitute
3
x
+
5
for
y
in
y
=
x
+
19
:
y
=
x
+
19
3
x
+
5
=
x
+
19
3
x
+
5
+
−
x
=
x
+
19
+
−
x
(Add -x to both sides)
2
x
+
5
=
19
2
x
+
5
+
−
5
=
19
+
−
5
(Add -5 to both sides)
2
x
=
14
2
x
2
=
14
2
(Divide both sides by 2)
x
=
7

Step: Substitute
7
for
x
in
y
=
3
x
+
5
:
y
=
3
x
+
5
y
=
(
3
)
(
7
)
+
5
y
=
26
(Simplify both sides of the equation)

Answer:
x
=
7
and
y
=
26
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Answer:

B and E

Step-by-step explanation:

0.5 ÷ 0.25 = 2

A. NO because it's 20

B. Yes

C. NO because it's 0.2

D. NO because it's 1.1 repeating

E. Yes

7 0
2 years ago
A personnel director interviewing 12 senior engineers for five job openings has scheduled seven interviews for the first day and
bezimeni [28]

Answer:

a) h(x; 7, 5, 12) = (⁵Cₓ)( ⁷C₇₋ₓ) / (¹²C₇)

b) 2.92

Step-by-step explanation:

a)

Here

Number of interviewees = N = 12

Number of job openings = M = 5

Interviews schedules for the first day =  n = 7

N − M = 12 - 5 = 7

Using hypergeometric distribution:

Let X be the no. top four candidates interviewed on first day.

The probability mass function of X:

P(X = x) = (^{M} C_{x})   (^{N-M} C_{n-x}) /  (^{N} C_{n})

It can be written as:

h(x; n, M, N)  =  (^{M} C_{x})   (^{N-M} C_{n-x}) /  (^{N} C_{n})    

                    = (5Cx) (7C7-x) / (12C7)

                    = (⁵Cₓ)( ⁷C₇₋ₓ) / (¹²C₇)

h(x; 7, 5, 12) = (⁵Cₓ)( ⁷C₇₋ₓ) / (¹²C₇)

b)

The expectation is: E(X) = np

E(X) = n * M/N

              = 7 * 5/12

              = 7 * 0.41667

              = 2.9167

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vlabodo [156]

Answer:

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3 0
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