The answer is 7 ok hduehdhd
Answer:
x=2 and XM=11
Step-by-step explanation:
because M is the midpoint of the line, you know that both XM and ZM are equal and you know an expression for the lengths of both of these.
set these expressions equal and solve:
4x+3=3x+5 so by subtracting the 3x from the right side, moving it over to the left and subtracting 3 from the left side to move it over to the right, you get:
x=2
then to find XM, plug in this value of x to get XM=11
4(2)+3=11
Answer:
Step-by-step explanation:
(-2, 3 ) ; (4 , 7)
Distance = ![\sqrt{(x_{2}-x_{1})^{2}+(y_{2}-y_{1})^{2}}](https://tex.z-dn.net/?f=%5Csqrt%7B%28x_%7B2%7D-x_%7B1%7D%29%5E%7B2%7D%2B%28y_%7B2%7D-y_%7B1%7D%29%5E%7B2%7D%7D)
![=\sqrt{(4-[-2])^{2}+(7-3)^{2}}\\\\=\sqrt{(4+2)^{2}+(7-3)^{2}}\\\\=\sqrt{6^{2}+4^{2}}\\\\=\sqrt{36+16}\\\\=\sqrt{52}\\\\=\sqrt{2*2*13}\\\\=2\sqrt{13}](https://tex.z-dn.net/?f=%3D%5Csqrt%7B%284-%5B-2%5D%29%5E%7B2%7D%2B%287-3%29%5E%7B2%7D%7D%5C%5C%5C%5C%3D%5Csqrt%7B%284%2B2%29%5E%7B2%7D%2B%287-3%29%5E%7B2%7D%7D%5C%5C%5C%5C%3D%5Csqrt%7B6%5E%7B2%7D%2B4%5E%7B2%7D%7D%5C%5C%5C%5C%3D%5Csqrt%7B36%2B16%7D%5C%5C%5C%5C%3D%5Csqrt%7B52%7D%5C%5C%5C%5C%3D%5Csqrt%7B2%2A2%2A13%7D%5C%5C%5C%5C%3D2%5Csqrt%7B13%7D)
Answer:
A. P(x>12 in 5 minutes)=0.0201
Step-by-step explanation:
Because we are working with a Poisson Distribution of probability, we need to get all the data needed. In a Poisson distribution is needed a constant called λ that symbolizes the mean data (6 calls) per unit of time (5 minutes), for this distribution λ=6/5.
Poisson probabilities work like this:
![P(x=y\ 'in\ z\ unit\ of\ time')= \frac{e^{-z\lambda}(z\lambda)^{y}}{y!}](https://tex.z-dn.net/?f=P%28x%3Dy%5C%20%27in%5C%20z%5C%20unit%5C%20of%5C%20time%27%29%3D%20%5Cfrac%7Be%5E%7B-z%5Clambda%7D%28z%5Clambda%29%5E%7By%7D%7D%7By%21%7D)
Remember y has to be an integer and the units of z must be the same unit of time used in λ. Now we are ready to solve this problem
A. The question is asking for the probability that in 5 minutes appear more calls than the phone-answering machine could answer (i.e P(x>12 in 5 minutes)). Because there are infinite numbers greater than 12, we are using this property of probabilities that´ll help us simplify the problem:
P(x>12 in 5 minutes)= 1 - P(x≤12 in 5 minutes)
Now we can use the following:
![P(x\geq12\ in\ 5\ minutes)=P(x=0\ in\ 5\ min)+P(x=1\ in\ 5\ min)+...P(x=12\ in\ 5\ min)](https://tex.z-dn.net/?f=P%28x%5Cgeq12%5C%20in%5C%205%5C%20minutes%29%3DP%28x%3D0%5C%20in%5C%205%5C%20min%29%2BP%28x%3D1%5C%20in%5C%205%5C%20min%29%2B...P%28x%3D12%5C%20in%5C%205%5C%20min%29)
![P(x\geq12\ in\ 5\ minutes)=\sum_{n=0}^{\infty}P(x=n\ in\ 5\min)](https://tex.z-dn.net/?f=P%28x%5Cgeq12%5C%20in%5C%205%5C%20minutes%29%3D%5Csum_%7Bn%3D0%7D%5E%7B%5Cinfty%7DP%28x%3Dn%5C%20in%5C%205%5Cmin%29)
![P(x\geq12\ in\ 5\ minutes)=\sum_{n=0}^{\infty}\frac{e^{-6}6^{n}}{n!}](https://tex.z-dn.net/?f=P%28x%5Cgeq12%5C%20in%5C%205%5C%20minutes%29%3D%5Csum_%7Bn%3D0%7D%5E%7B%5Cinfty%7D%5Cfrac%7Be%5E%7B-6%7D6%5E%7Bn%7D%7D%7Bn%21%7D)
And you can find P(x=n in 5 minutes) for every n using a calculator or a computer, and finally add them to get
P(x≤12 in 5 minutes)= 0.9799
P(x>12 in 5 minutes)= 1-0.9799
This will be our answer
P(x>12 in 5 minutes)= 0.0201