Most
importantly, while including divisions with various denominators, the initial
step says that we should change these portions so they have "a similar
denominator" .Here are the means for including divisions with various
denominators .Construct each portion with the goal that the two denominators
are equivalent. Keep in mind, while including divisions with various
denominators, the denominators must be the same.
So
we should finish this progression first.
<span>a. Re-compose every proportionate division
utilizing this new denominator </span>
<span>b. Now you can include the numerators, and
keep the denominator of the proportionate divisions. </span>
<span>c. Re-compose your answer as a streamlined
or decreased division, if necessary. </span>
We know this sound like a great deal of work,
and it is, yet once you see completely how to locate the Common Denominator or
the LCD, and manufacture proportional parts, everything else will begin to
become all-good. Thus, how about we set aside our opportunity to do it.
Solution:
5b/4a + b/3a -3b/a
=15b/12a + 4b/12a – 36b/12a
= -17b/12 a
Or
<span>= - 1 5b/12a in lowest term.
</span>
If 6 and 12 are 2 positive number then there should be 2 for each one of them
Answer:
x = 20
Step-by-step explanation:
The sum of the 3 angles in a triangle = 180°
Using ΔAHC , then
∠ACH = 180 - (2x + 100) = 180 - 2x - 100 = 80 - 2x
∠ECD = ∠ACB ( vertical angles are congruent ), thus
∠ECD = ∠ACH + ∠HCB, that is
3x = 80 - 2x + x
3x = 80 - x ( add x to both sides )
4x = 80 ( divide both sides by 4 )
x = 20
Answer:
10y-30
Step-by-step explanation:
10*1y=10y
-3*10=-30
10y-30
