9a^2-6ab+12ac-8bc
=3a(3a-2b)+4c(3a-2b)
=(3a+4c)(3a-2b)
There you go. Have fun!
The local minimum of function is an argument x for which the first derivative of function g(x) is equal to zero, so:
g'(x)=0
g'(x)=(x^4-5x^2+4)'=4x^3-10x=0
x(4x^2-10)=0
x=0 or 4x^2-10=0
4x^2-10=0 /4
x^2-10/4=0
x^2-5/2=0
[x-sqrt(5/2)][x+sqrt(5/2)]=0
Now we have to check wchich argument gives the minimum value from x=0, x=sqrt(5/2) and x=-sqrt(5/2).
g(0)=4
g(sqrt(5/2))=25/4-5*5/2+4=4-25/4=-9/4
g(-sqrt(5/2))=-9/4
The answer is sqrt(5/2) and -sqrt(5/2).
Answer:
a lot
Step-by-step explanation:
Answer:
Nonstatistical= HOW MANY ORANGES DID SALLY AT LAST MONTH, HOW MANY HOURS DID I SPEND ON EXTRA CIRICULA..., and HOW MANY DOGS DO I HAVE
Statistical: The other ones.
Step-by-step explanation: Please Tell me if it was Wrong.
Answer:
176
Step-by-step explanation:
88% = 88/100
88 × 2 = 176
176/200