Step 1- Multiply both sides by 8.
Step 2- Simplify 3 x 8 to 24.
Answer = x > 24
Answer:
0.128
Step-by-step explanation:
We know the probability for any event X is given by,
,
where p is the probability of success and q is the probability of failure.
Here, we are given that p = 0.533.
Since, we have that q = 1 - p
i.e. q = 1 - 0.533
i.e. q = 0.467
It is required to find the probability of 4 wins in the next 5 games i.e. P(X=4) when n = 5.
Substituting the values in the above formula, we get,
![P(X=4)=\binom{5}{4}\times 0.533^{5-4}\times 0.467^{4}](https://tex.z-dn.net/?f=P%28X%3D4%29%3D%5Cbinom%7B5%7D%7B4%7D%5Ctimes%200.533%5E%7B5-4%7D%5Ctimes%200.467%5E%7B4%7D)
i.e. ![P(X=4)=5 \times 0.533 \times 0.048](https://tex.z-dn.net/?f=P%28X%3D4%29%3D5%20%5Ctimes%200.533%20%5Ctimes%200.048)
i.e. ![P(X=4)=5 \times 0.533 \times 0.048](https://tex.z-dn.net/?f=P%28X%3D4%29%3D5%20%5Ctimes%200.533%20%5Ctimes%200.048)
i.e. i.e. ![P(X=4)=0.128](https://tex.z-dn.net/?f=P%28X%3D4%29%3D0.128)
Hence, the probability of 4 wins in the next 5 games is 0.128.
Answer:
0.0854
Step-by-step explanation:
= 0.0854
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Answer:
X : ___ 0 ____ 1 _____ 2 ______ 3
P(X) : _ 6/15 __ 5/15__ 3/15 ____ 1/15
Step-by-step explanation:
From the data, to produce a probability distribution for the data :
X : number of times blood is drawn ;
P(x) : probability that blood is drawn at X times
Hence, the probability distribution table for the data Given goes thus :
X : ___ 0 ____ 1 _____ 2 ______ 3
P(X) : _ 6/15 __ 5/15__ 3/15 ____ 1/15
Probability that blood is drawn 0 times = 6/15
Probability that blood is drawn 1 time = 5/15
Probability that blood is drawn 2 times = 3/15
Probability that blood is drawn 3 times = 1/15
(6/15 + 5/15 + 3/15 + 1/15) = 1