2 years ago

Subtract the cube root of the product of h and 3k from the square of the sum of p and q

Mathematics

1 answer:

ehidna [41]2 years ago

3 0

Answer:

(p + q)² - ∛(h·3k) or (p + q)² - ∛(h·3k)

Step-by-step explanation:

Cube root of x: ∛x

Product of h and 3k: h·3k

Sum of p and q: p + q

*****************************

From (p + q)² subtract ∛(h·3k) This becomes, symbolically:

=> (p + q)² - ∛(h·3k)

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Subtract the cube root of the product of h and 3k from the square of the sum of p and q​

Subtract the cube root of the product of h and 3k from the square of the sum of p and q