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3 years ago

Which of these quadrilateral types must have all four sides congruent?

Mathematics

2 answers:

Ronch [10]3 years ago

8 0

Answer:

Option D is correct

Step-by-step explanation:

Rectangle, square, rhombus must have all four sides congruent.

<h3>Hope it is helpful...</h3>

Paraphin [41]3 years ago

3 0

C. Square & rhombus

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Help on geometry work?

Likurg_2 [28]

D=122 degrees, hope this helps!!

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3 years ago

there are 266 students watching a play in the auditorium. there 10 rows with 20 students in each row and 5 rows with 8 students

kondor19780726 [428]

Let x = number of students in each of the remaining rows

266 = (10 x 20) + (5 x 8) + 2x
266 - (10 x 20) - (5 x 8) = 2x
266 - 200 - 40 = 2x
26 = 2x
x = 26/2
x = 13

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This robotic arm is made up of two cylinders with equal volume and two triangular prism hands. The volume of each hand is

BaLLatris [955]

Answer:

$\frac{r}{3\pi h+r}$

Step-by-step explanation:

Since the height isn't given, we assume it to be "h" (of cylinders). And the answer will be in terms of "r" and "h".

The area of 1 arm is given, so the area of 2 arms would be:

$A_{arm}=2*(\frac{1}{2}r*\frac{1}{3}r*2r)=\frac{2r^3}{3}$

Now, area of 2 cylinders would be the formula:

$A_{cyl}=2*(\pi r^2 h)=2\pi r^2 h$

So, total area is A_arm PLUS A_cyl. The fractional area the arms are would be gotten by taking expression A_arm divided by A_total.

Shown below:

$\frac{A_{arm}}{A_{total}}=\frac{\frac{2r^3}{3}}{2\pi r^2 h + \frac{2r^3}{3}}$

We simplify further:

$\frac{\frac{2r^3}{3}}{2\pi r^2 h + \frac{2r^3}{3}}\\=\frac{\frac{2r^3}{3}}{2r^2(\pi h + \frac{r}{3})}\\=\frac{r}{3(\pi h + \frac{r}{3})}\\=\frac{r}{3\pi h+r}$

THis is the answer.

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3 years ago

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The sum of 3y and 5 is 47

Daniel [21]

if 3y + 5 = 47

then

y=14

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3 years ago

The sum of three consecutive even integers is 258. write an equation ad solve to find the integers

slavikrds [6]

The consecutive integers are 85,86,87

Explanation:

the first number

the second number

the third number

(

)

(

)

258

−

255

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3 years ago

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