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Mnenie [13.5K]
3 years ago
11

Which is the next step in following construction of a regular hexagon

Mathematics
2 answers:
Arlecino [84]3 years ago
7 0

Answer:With compass setting the same as line segment PA, place the compass  at C and draw an arc that intersects the circle

<h3>Step-by-step explanation:</h3>

Lets revise the step of construction a regular hexagon

1. Draw circle with center P; put point A on the circle's edge at

any place

2. With compass setting the same as line segment PA, place the

compass at A and draw an arc that intersects the circle at B

3. With compass setting the same as line segment PA, place the

compass at B and draw an arc that intersects the circle at C

4. With compass setting the same as line segment PA, place the

compass at C and draw an arc that intersects the circle at D

5. Contain with the same step of placing the compass at the previous arc and draw an arc with same distance of PA until you reach point A again, then join each arc on the circle forming the regular hexagon

The given steps are:

Circle with center P; point A is along the circles edge, an arc at point B

is along the circles edge, and an arc at point C is along the circles edge

According to the steps above, the next step is:

With compass setting the same as line segment PA, place the

compass at C and draw an arc that intersects the circle (step 4)

:>

irinina [24]3 years ago
5 0

Answer:

The square is the next step

Step-by-step explanation:

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Answer:

  24.  see below for a drawing with axis intercepts labeled

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24. The axis intercepts are fairly easily found. You can do it a couple of ways.

<u>first way</u>

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For 3x +5y +15z = 15, the x-intercept can be found by setting y and z to zero. This gives ...

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so, dividing by 3 tells you the x-intercept is ...

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Likewise, the y- and z-intercepts are, respectively, ...

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So, the points where the plane crosses the axes are ...

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<u>second way</u>

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Doing that gives ...

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From the above equation, we see the axis intercepts are ...

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Actually, the math for these two methods is virtually identical. The second way does it "all at once", so can take fewer steps. Effectively, you're doing the math of the "first way" and expressing the result in the denominator.

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Please note that when a variable is missing, there is no intercept for that axis. That is, the plane is parallel to that axis. (In problem 30, for example, the y- and z-variables are missing. The plane x=4 is parallel to the y- and z-axes (the y-z plane).)

_____

In the first attached drawing, the x-axis is red, the y-axis is green, and the z-axis is blue. The labeling of the points is difficult to see, but the axes are a different (lighter) color behind the plane than in front of it. This plane forms a triangle in the first octant (x, y, z > 0).

In the second attached drawing, the x=0 plane is blue; the y=0 plane is green, and the z=0 plane is red. The plane of the equation is yellow. This figure better shows the triangle in the first octant.

3-D graph paper (isometric graph paper) grids are available with a web search. Such might make it easier to draw the planes you need to draw. (See the third attachment for one example.)

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