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iragen [17]
4 years ago
12

PLZ HELP!!! BRAINLYEST WILL BE GIVEN TO BEST ANSWER!!!! IF YOU PUT A LINK I WILL REPORT YOU!!!!! DONT TRY ME!!!!!! YALL BEEN WAS

TING MY POINTS LATELY I HATE IT SO NO SNEAKY LINK OR NON ANSWER OR U WILL BE REPORTED.
PLZ HELP!!! BRAINLYEST WILL BE GIVEN TO BEST ANSWER!!!! IF YOU PUT A LINK I WILL REPORT YOU!!!!! DONT TRY ME!!!!!! YALL BEEN WASTING MY POINTS LATELY I HATE IT SO NO SNEAKY LINK OR NON ANSWER OR U WILL BE REPORTED.

I PUT IT TWICE BECAUSE U PEOPLE DONT GET IT!!!!!
NO LINKS OR NON ANSWERS!!!!
DONT MAKE ME GO CRAZY!!!!

Mathematics
1 answer:
Nataliya [291]4 years ago
4 0

Answer:

2209

Step-by-step explanation:

The interquartile range is the 3rd quartile minus the 1st quartile. To find the quartiles, you need to find the median.

First, put the values in order.

17012, 18140, 17362, 16697, 14387 becomes

14387, 16697, 17012, 17362, 18140

The median is the value in the middle, so 17012. The first quartile is the median of the numbers to the <em>left</em> of the median. The numbers to the left are 14387 and 16697. Because there are an even amount of numbers, there's no middle. So the median of those values is the average (aka the sum divided by the number of values).

14387 + 16697 = 31084. Then divide that by 2 (the number of values) and you get 15542. So 15542 is the first quartile.

The 3rd quartile is the median of the values to the <em>right. </em>It is 17751 because 17362 and 18140 are the numbers to the right of the median. 17362 + 18140 = 35502 and 35502/2 = 17751.

The interquartile range is the 3rd quartile minus the 1st quartile

17751 - 15542 = 2209

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P(WWC) = P(W) \times P(W) \times P(C) \\ \\ P(WWC) = \frac{3}{4} \times \frac{3}{4} \times \frac{1}{4} \\ \\ P(WWC) = \frac{9}{64}

P(WCW ) = P(W) \times P( C ) \times P(W) \\ \\ P(WCW) = \frac{3}{4} \times \frac{1}{4} \times \frac{3}{4} \\ \\ P(WCW) = \frac{9}{64}

P(CWW ) = P(W) \times P( C ) \times P(W) \\ \\ P(CWW) = \frac{1}{4} \times \frac{3}{4} \times \frac{3}{4} \\ \\ P(CWW) = \frac{9}{64}

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