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Mama L [17]
4 years ago
9

NO LINKS OR ELSE YOU'LL BE REPORTED!Only answer if you're very good at Math.No guessing please.

Mathematics
2 answers:
Yuki888 [10]4 years ago
5 0
C due to the fact that it is C and C is the correct answer
puteri [66]4 years ago
5 0

Answer:

16 3/2

Step-by-step explanation:

So lets go thru each one.

16 3/2 is just 17.5

A square root cancels out a square.

A cubed root cancels out a cube.

So, in the next answer:

16 squared, to the square root is just 16, since the squaring and root cancels out.

64 sqaured to the cube root must be 16. Lets break it all down:

2^6=64.  We need to square this, so we can rewrite it as:

64^2 = (2^6)^2

Normally we add/subtract exponents, but since the 6 exponent is in parethesese, it is multiplied by the 2 exponent. This makes it 2^12. So we can rewrite \sqrt[3]{64^2} as:

\sqrt[3]{2^1^2}

Now, when we divide a exponent by a exponent, we subtract.

However, when we root a exponent, it is division.

So it is the 2 \frac{^1^2}{^3}

=

2^4

Or

16

Finally we have the cubed root of 8^4.

using the same steps as above, 8^4 = (2^3)^4. This equals 2^1^2

Then again, we cube root it.

This is division of the 12 exponent by the 3 root, so we get:

2^4

=

16

So in the end:

A - 17.5

B - 16

C - 16

D - 16

So a is the largest number

Hope this helps!

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Square root of the quantity x minus 2 end quantity plus 8 equals x
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ANSWER

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EXPLANATION

We want to solve the equation:

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Rewrite in the form ax² +bx+c=0

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This implies that,

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Checking for extraneous solutions.

When x=6, the original equation becomes,

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x=6 is an extraneous solution.

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\sqrt{11- 2}  + 8 = 11

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This is true, hence x=11 is the only solution.

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