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kap26 [50]
3 years ago
5

10. There are sees in Mt. Pisher's PE class. There are so se gradies and 25 graders in the case

Mathematics
1 answer:
Zolol [24]3 years ago
6 0

Answer:

i dont under stand sorry i cant help sorry

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It costs miksel $4 to make a bike bag, if he sells each gor $5. He has made a profit of $16 dollars so far
mixas84 [53]

Answer:

16

Step-by-step explanation:

5-4 = 1 so total profit would be $1 for each bag.

Because he makes 1 dollar per bag this is a fairly simple to see how many he has but we will pretend its not so you have an idea of how to do this later.

You should divide the final profit he's made by the total he gets per each, which would give you how many he has made.

$16/$1 = 16 bags produced.

4 0
3 years ago
How do I solve 1/10x+5=-3x-13+4x ?
Temka [501]

Answer:

x = 20

I am not sure if you wanted the answer. Sorry!

Step-by-step explanation:

Let's solve your equation step-by-step.

1/10 x + 5 = - 3x - 13 + 4x

Step 1: Simplify both sides of the equation.

1/10 x + 5 = - 3x - 13 + 4x

1/10 x + 5 = - 3x + - 13 + 4x

1/10 x + 5 = (<em>- 3x + 4x</em>) + (- 13)

1/10 x + 5 = <em>x</em> + - 13

1/10 x + 5 = x - 13

Step 2: Subtract x from both sides.

1/10 x + 5 - <em>x </em>= x - 13 - <em>x</em>

- 9/10 x + 5 = - 13

Step 3: Subtract 5 from both sides

- 9/10 x + 5 - <em>5</em> = - 13 - <em>5</em>

- 9/10 x = - 18

Step 4: Multiply both sides by 10/(- 9).

(<em>10/ - 9</em>) * (- 9/10 x) = (<em>01/ - 9</em>) * (- 18)

x = 20

Hope this helps!

4 0
3 years ago
Read 2 more answers
Please find the surface area of each figure to the nearest tenth? Please show the work too...
MrRa [10]
The first one is 31.875 and the second is 12 I don't know how to explain to get it. Sorry
7 0
3 years ago
What are the solutions of 3x^2-x+4=0
guajiro [1.7K]
3x² -x+4=0

We can use quadratic formula
a=3, b= -1, c=4
 x=  \frac{-b+/- \sqrt{b^{2}-4ac} }{2a}  &#10;\\ \\ x= \frac{1+/- \sqrt{1-4*3*4} }{2*3} &#10;\\ \\ x =  \frac{1+/- \sqrt{-47} }{6} &#10;&#10;This equation does not have real  roots, it has only 2 imaginary roots.

x= \frac{1+ \sqrt{47}i }{6} &#10;\\ \\ x=  \frac{1- \sqrt{47}i }{6}


6 0
3 years ago
Rounded to the nearest hundredth, what is the positive solution to the quadratic equation 0 = 2x2 + 3x – 8?
zmey [24]
2x² + 3x -8 = 0

a = 2 , b = 3 , c = -8
So..
D = b²-4ac = 9 + 64 = 73

for bigger solution , use x = -b + √D / 2a
For smaller solution, use x = -b - √D / 2a

So
= -3 + √73 / 2. 2
= 1/4 (√73 -3)

Hopefully helpfull.. ^_^
8 0
3 years ago
Read 2 more answers
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