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SIZIF [17.4K]
3 years ago
13

Which pair of ratios is proportional?

Mathematics
2 answers:
liberstina [14]3 years ago
5 0

Answer:

Picture? Image? Where's the question?

Step-by-step explanation:

A proportional ratio is when two ratios are equivalent.

Alisiya [41]3 years ago
4 0

Answer:

Ratios are proportional if they represent the same relationship.

Step-by-step explanation:

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500 divide 10/2 and divide 5 and times x divide 5
coldgirl [10]
(500 / (10/2) / 5 ) * x / 5 = 20 * x / 5 = (20 / 5) * x = 4 * x
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3 years ago
Solve for x:a(a²+b²)x²+b²x-a​
m_a_m_a [10]

Answer:

x = a/(a² + b²) or x = -1/a  

Step-by-step explanation:

a(a²+ b²)x² + b²x - a =0

Use the quadratic equation formula:

x = \dfrac{-b\pm\sqrt{b^2-4ac}}{2a} =\dfrac{-b\pm\sqrt{D}}{2a}

1. Evaluate the discriminant D

D = b² - 4ac = b⁴ - 4a(a² + b²)(-a) = b⁴ + 4a⁴ + 4a²b²  = (b² + 2a²)²

2. Solve for x

\begin{array}{rcl}x & = & \dfrac{-b\pm\sqrt{D}}{2a}\\\\ & = & \dfrac{-b^{2}\pm\sqrt{(b^{2}+2a^{2})^{2}}}{2a(a^{2} + b^{2})}\\\\ & = & \dfrac{-b^{2}\pm(b^{2}+ 2a^{2})}{2a(a^{2} + b^{2})}\\\\x = \dfrac{-b^{2}+(b^{2} + 2a^{2})}{2a(a^{2} + b^{2})}&\qquad& x =\dfrac{-b^{2}-(b^{2} + 2a^{2})}{2a(a^{2} + b^{2})}\\\\x =\dfrac{-b^{2}+(b^{2} + 2a^{2})}{2a(a^{2} + b^{2})}&\qquad& x =\dfrac{-b^{2}-(b^{2} +2a^{2})}{2a(a^{2} + b^{2})}\\\\\end{array}

\begin{array}{rcl}x = \large \boxed{\mathbf{\dfrac{a}{a^{2} + b^{2}}}}&\qquad& x =\dfrac{-b^{2}-(b^{2} +2a^{2})}{2a(a^{2} + b^{2})}\\\\&\qquad& x =\dfrac{-2b^{2}- 2a^{2}}{2a(a^{2} + b^{2})}\\\\&\qquad& x =\dfrac{-2(a^{2}+ b^{2})}{2a(a^{2} + b^{2})}\\\\&\qquad& x =\large \boxed{\mathbf{-\dfrac{1}{a}}}\\\\\end{array}

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3 years ago
Which table represents the function?
horrorfan [7]
D because they all increase by the same number (+1)
7 0
3 years ago
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Solve for x and graph the solution on the number line<br> 15 &gt; 2x – 9 &gt; -23
Monica [59]

The answer is 12>x>-7

Step-by-step explanation:

it's first divided into 2 parts

1 . 15 > 2x - 9

2. 2x - 9 > -23

Then solve them individually.

let's do it,

<u>First half</u>

15 > 2x - 9

15+9 > 2x

24 > 2x

24/2 > x

12>x

<u>Second half</u>

2x-9>-23

2x>-23+9

2x>-14

x>-14/2

x>-7

<u>Joining of the two halves</u>

We have :

12>x>-7

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