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2 years ago

The cost of a phone call at a hotel is determined by the formula

Mathematics

1 answer:

dimulka [17.4K]2 years ago

8 0

C = $5.85

$5.85 = 0.35t + 0.6
-.6 -.6

$5.25 = 0.35t
------- --------
.35 .35

15 = t

15 minutes

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in a proportional relationship the ratio y/x is constant. Show that this ratio is not constant for the equation y=a-14

Colt1911 [192]

To show that the ratio $\frac{y}{x}$ is not constant for the function $y=a-14$ we only need to evaluate this function at 2 points and then show that the ratio is not the same for those two points. Note that here $a$ represents $x$ .

To find the counter examples here, I will use the values $a=20$ and $a=28$ . For $a = 20$ , the equation tells us that the output is

$y=20-14=6$ . For this value of $a$ the point is point is $(20,6)$ . The ratio $\frac{y}{x} =\frac{6}{20}$ . For the $a=28$ , $y=28-14=14$ . For this value of $a$ the point is $(28,14)$ . The ratio $\frac{y}{x} =\frac{14}{28} =\frac{1}{2}$ . Clearly this ratio is not constant for all ordered pairs.

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2 years ago

A cell phone provider offers a plan that costs $30 per month plus $0.10 per text message sent or received. A comparable plan c

mariarad [96]

300 messages would have to be sent or received in order for the plan to cost same each month.

Step-by-step explanation:

Given,

Cost per month = $30

Per text sent or received charges = $0.10

Let,

x be the number of texts sent or received.

A(x) = 0.10x+30

A comparable plan costs = $60 per month

Text messages are unlimited.

B(x) = 60

For the two plans to cost equal;

A(x) = B(x)

$0.10x+30=60\\0.10x=60-30\\0.10x=30$

Dividing both sides by 0.10

$\frac{0.10x}{0.10}=\frac{30}{0.10}\\x=300$

300 messages would have to be sent or received in order for the plan to cost same each month.

Keywords: function, addition

Learn more about functions at:

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3 years ago

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evablogger [386]

1 and 5/16 pounds
Divide 7/8 with 2/3

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3 years ago

What is the answer to 3(5)

zmey [24]

Answer: 15

Step-by-step explanation:

3x5=15

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2 years ago

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Find an equation of the plane consisting of all points that are equidistant from (-3, 5, -4) and (-5, 0, 4), and having -2 as th

Firdavs [7]

Answer:

-2x-5y+8z+4.5=0

Step-by-step explanation:

Let (x,y,z) be the coordinates of the point lying on the needed plane. This point is equidistant from the points (-3, 5, -4) and (-5, 0, 4), so

$d_1=\sqrt{(x-(-3))^2+(y-5)^2+(z-(-4))^2}=\sqrt{(x+3)^2+(y-5)^2+(z+4)^2}\\ \\d_2=\sqrt{(x-(-5))^2+(y-0)^2+(z-4)^2}=\sqrt{(x+5)^2+y^2+(z-4)^2}\\ \\d_1=d_2\Rightarrow \sqrt{(x+3)^2+(y-5)^2+(z+4)^2}=\sqrt{(x+5)^2+y^2+(z-4)^2}\\ \\(x+3)^2+(y-5)^2+(z+4)^2=(x+5)^2+y^2+(z-4)^2\\ \\x^2+6x+9+y^2-10y+25+z^2+8z+16=x^2+10x+25+y^2+z^2-8z+16\\ \\-4x-10y+16z+9=0\\ \\-2x-5y+8z+4.5=0$

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2 years ago

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