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3 years ago

Simplify each expression by combining like terms 4x+7x=

Mathematics

2 answers:

STALIN [3.7K]3 years ago

7 0

Answer:

11x

Step-by-step explanation:

Natalka [10]3 years ago

7 0

11x (add the like terms)

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Solve. x3 ≤ -6 A) x ≤ -2 B) x ≥ -2 C) x ≤ -12 D) x ≤ -18

TiliK225 [7]

Answer:a

Step-by-step explanation:injust took the test on USATESTPREP

6 0

3 years ago

Indicate the equation of the line that is the perpendicular bisector of the segment with endpoints (4, 1) and (2, -5).

PtichkaEL [24]

Okay to find the perpendicular bisector of a segment you first need to find the slope of the reference segment.

m=(y2-y1)/(x2-x1) in this case:

m=(-5-1)/(2-4)

m=-6/-2

m=3

Now for the the bisector line to be perpendicular its slope must be the negative reciprocal of the reference segment, mathematically:

m1*m2=-1 in this case:

3m=-1

m=-1/3

So now we know that the slope is -1/3 we need to find the midpoint of the line segment that we are bisecting. The midpoint is simply the average of the coordinates of the endpoints, mathematically:

mp=((x1+x2)/2, (y1+y2)/2), in this case:

mp=((4+2)/2, (1-5)/2)

mp=(6/2, -4/2)

mp=(3,-2)

So our bisector must pass through the midpoint, or (3,-2) and have a slope of -1/3 so we can say:

y=mx+b, where m=slope and b=y-intercept, and given what we know:

-2=(-1/3)3+b

-2=-3/3+b

-2=-1+b

-1=b

So now we have the complete equation of the perpendicular bisector...

y=-x/3-1 or more neatly in my opinion :P

y=(-x-3)/3

4 0

3 years ago

Read 2 more answers

Find a number which in which added square sum will be 72.

Tom [10]

Answer:

8.48528137424^2

Step-by-step explanation:

8.48528137424x8.48528137424

= 72

7 0

3 years ago

<img src="https://tex.z-dn.net/?f=%20%5Crm%20%5Cint_%7B0%7D%5E%7B%20%20%5Cpi%20%7D%20%5Ccos%28%20%5Ccot%28x%29%20%20%20%20-%20%2

Nikolay [14]

Replace x with π/2 - x to get the equivalent integral

$\displaystyle \int_{-\frac\pi2}^{\frac\pi2} \cos(\cot(x) - \tan(x)) \, dx$

but the integrand is even, so this is really just

$\displaystyle 2 \int_0^{\frac\pi2} \cos(\cot(x) - \tan(x)) \, dx$

Substitute x = 1/2 arccot(u/2), which transforms the integral to

$\displaystyle 2 \int_{-\infty}^\infty \frac{\cos(u)}{u^2+4} \, du$

There are lots of ways to compute this. What I did was to consider the complex contour integral

$\displaystyle \int_\gamma \frac{e^{iz}}{z^2+4} \, dz$

where γ is a semicircle in the complex plane with its diameter joining (-R, 0) and (R, 0) on the real axis. A bound for the integral over the arc of the circle is estimated to be

$\displaystyle \left|\int_{z=Re^{i0}}^{z=Re^{i\pi}} f(z) \, dz\right| \le \frac{\pi R}{|R^2-4|}$

which vanishes as R goes to ∞. Then by the residue theorem, we have in the limit

$\displaystyle \int_{-\infty}^\infty \frac{\cos(x)}{x^2+4} \, dx = 2\pi i {} \mathrm{Res}\left(\frac{e^{iz}}{z^2+4},z=2i\right) = \frac\pi{2e^2}$

and it follows that

$\displaystyle \int_0^\pi \cos(\cot(x)-\tan(x)) \, dx = \boxed{\frac\pi{e^2}}$

7 0

2 years ago

It takes

kati45 [8]

Answer:

I don't really know if this is a trick question or not but, is 6363 minutes the answer?

Step-by-step explanation:

8 0

3 years ago