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galina1969 [7]
3 years ago
12

Which expression can be used to find the product of 720?

Mathematics
1 answer:
Flauer [41]3 years ago
8 0

Answer:

(8 x 9) x (2 x 5) is the correct answer.

Step-by-step explanation:

(8 x 9)= 72

(2 x 5)= 10

72 x 10 = 720

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Use synthetic division to solve (x^3+1)/(x-1). What is the quotient?
Sav [38]

Answer:

  x^2 +x +1

Step-by-step explanation:

See below for the tableau. The quotient is x^2 +x +1.

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The remainder is 2.

7 0
3 years ago
two sides of a triangle are 4 and 6 the third side cant be what A 2 b 4 c 6 d 8 please respond asap ​
noname [10]

Answer:

it’s b.4

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8 0
3 years ago
If the area of a rectangle is 162 square meters, what is the length of the base
Contact [7]

Answer:

If the long side is down then the length of the base is 81 sq.m.

If the short side is down then the length of the base is 20.25 sq.m.

Step-by-step explanation:

162/4 is 40.5 that means if this were a square it would be 40.5 sq.m. On each side, if the base is longer you multiply 40.5 by 2 (or whatever youre supposed to honestl) and if the base is shorter you divide by 2 (or whatever you were supposed to)

7 0
3 years ago
*nervous laugh* SO ummm geometry isnt my thing actually im rather bad it please help!
Savatey [412]
I believe the answer would be D 92 and 88 hope it helped 
8 0
3 years ago
Read 2 more answers
a rectangular box with two sqaure opposite ends is to hold 8000 cubic inches. find the dimensions of the cheapest box if tge rec
AveGali [126]

Answer:

the dimensions of the box that minimizes the cost are 5 in x 40 in x 40 in

Step-by-step explanation:

since the box has a volume V

V= x*y*z = b=8000 in³

since y=z (square face)

V= x*y² = b=8000 in³

and the cost function is

cost = cost of the square faces *  area of square faces + cost of top and bottom * top and bottom areas + cost of the rectangular sides * area of the rectangular sides

C = a* 2*y² +  a* 2*x*y + 15*a* 2*x*y =  2*a* y² +  32*a*x*y

to find the optimum we can use Lagrange multipliers , then we have 3  simultaneous equations:

x*y*z = b

Cx - λ*Vx = 0 → 32*a*y -  λ*y² = 0 → y*( 32*a-λ*y) = 0 → y=32*a/λ

Cy - λ*Vy = 0  → (4*a*y + 32*a*x) - λ*2*x*y = 0

4*a*32/λ  + 32*a*x - λ*2*x*32*a/λ = 0

128*a² /λ +  32*a*x - 64*a*x = 0

32*a*x = 128*a² /λ

x  = 4*a/λ

x*y² = b

4*a/λ * (32*a/λ)² = b

(a/λ)³ *4096 =  8000 m³

(a/λ) = ∛ ( 8000 m³/4096 ) = 5/4 in

then

x  = 4*a/λ = 4*5/4 in = 5 in

y=32*a/λ = 32*5/4 in = 40 in

then the box has dimensions 5 in x 40 in x 40 in

3 0
3 years ago
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