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ICE Princess25 [194]
3 years ago
13

Nates classroom has three tables

Mathematics
2 answers:
KIM [24]3 years ago
7 0

'Nates classroom has three tables'

Well, that's true.

AleksandrR [38]3 years ago
7 0
With a 3x5 feet circumference. if each foot on the circumference could sit one child each, how many children are in Nate's classroom
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What is the means-to-MAD ratio of the two data sets, expressed as a decimal to the nearest tenth? Data Set 1: {85, 83, 90, 70, 8
RoseWind [281]
Here is what I got for the first one. MAD= 1/(N)*(|x1-xm|+|x2-xm|+..+|xN-xm|) =1/5(|85-83|+|83-83|+|87-83|+|90-83|+|70-83|) =1/5(2+0+4+7+13)) =5.2 And for the second one I got, MAD= 1/(N)*(|x1-xm|+|x2-xm|+..+|xN-xm|) =1/5(|75-76|+|74-76|+|68-76|+|83-76|+|80-76|) =1/5(1+2+8+7+4)) =4.4
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4 years ago
Anyone want to join a tournament in fort.nite im looking for players on brainly and putting them up against each other my You.Tu
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Sure! :))))))))!!!!!
7 0
3 years ago
Parker grew
vladimir1956 [14]

Answer:

63

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
How do I solve this <br> 4 - 2 3/9 =
AlladinOne [14]

Answer:

1 2/3.

Step-by-step explanation:

4 - 2 3/9

= 4 - 2 1/3

= 4 - 7/3

= 12/3 - 7/3

= 5/3

= 1 2/3

4 0
3 years ago
Given that α and β are the roots of the quadratic equation <img src="https://tex.z-dn.net/?f=2x%5E%7B2%7D%20%2B6x-7%3Dp" id="Tex
siniylev [52]

Answer:

\large \boxed{\sf \ \ \ p=-11 \ \ \ }

Step-by-step explanation:

Hello,

\alpha \text{ and } \beta \text{ are the roots of the following equation}

   2x^2+6x-7=p

It means that

   2\alpha^2+6\alpha-7=p \\\\2\beta ^2+6\beta -7=p \\\\

And we know that

\alpha= 2\cdot \beta

So we got two equations

   2(2\beta)^2+6\cdot 2 \cdot \beta -7=p \\\\8\beta^2+12\beta -7=p\\\\ and \ 2\beta ^2+6\beta -7=p \ So \\\\\\8\beta^2+12\beta -7 = 2\beta ^2+6\beta -7\\\\6\beta^2+6\beta =0\\\\\beta(\beta+1)=0\\\\ \beta =0 \ or \ \beta=-1

For \beta =0, \ \ \alpha =0, \ \ p = -7

For \beta =-1, \ \ \alpha =-2, \ \ p= 2-6-7=-11, \ p=2*4-12-7=-11

I assume that we are after two different roots so the solution for p is p=-11

b) \alpha +2 =-2+2=0 \ and \ \beta+2=-1+2=1

So a quadratic equation with the expected roots  is

x(x-1)=x^2-x

Hope this helps.

Do not hesitate if you need further explanation.

Thank you

3 0
3 years ago
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