A radius of a circle is 14 cm and a chord has 18 cm. What is the distance between the center of the circle and the chord

Mathematics

1 answer:

ryzh [129]3 years ago

6 0

Answer: $10.72\ cm$

Step-by-step explanation:

Given

Radius of circle $r=14\ cm$

Length of chord is $l=18\ cm$

Suppose the distance between the chord and center is x

From figure, we can write

$\Rightarrow r^2=x^2+9^2\\\Rightarrow 14^2=x^2+9^2\\\Rightarrow x^2=196-81\\\Rightarrow x^2=115\\\Rightarrow x=\sqrt{115}\\\Rightarrow x=10.72\ cm$

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My common core lesson 7 3.1

Verizon [17]

What is the question?

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3 years ago

Select two polynomials that have a sum of 16n^3+13n^2+7n-10 A. 8n^3 - 5n +11n^2 - 5 B. 7n^2 + 8n - n^3 + 2 C. 15n^2 - 10n + 3n^3

andreyandreev [35.5K]

Answer:

Step-by-step explanation:

We have the polynomial

$16n^3+13n^2+7n-10$ ( 1 )

To solve this problem we have to take into account that only we can sum term with the same order in the variable. We have the polynomials

$8n_{3}-5n+11n^{2}-5\\7n^2 + 8n - n^3 + 2\\15n^2 - 10n + 3n^3 - 4\\2n^2 + 12n - 5 + 8n^3$

we can note (by summing term by term) that only the sum of the first and the fourth equation correspond to the given polynomial ( 1 ) of the problem. If we organize these polynomials (that is, write the equation down in a form where higher order appears first ) we have

$8n^3 +11n^2 - 5n - 5\\ 8n^3+2n^2 + 12n - 5\\$