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3 years ago

7x+5y=-13 -2x=7y+26 Solve by elimination

Mathematics

2 answers:

RSB [31]3 years ago

5 0

Answer:

Point form : (1,-4)

Equation for, : x=1, y=-4

Step-by-step explanation: Add the fractions in order to solve for the first variable. Plug this vale into the other equations in order to solve for the remaining variables.

Hope this helps you out! ☺

11Alexandr11 [23.1K]3 years ago

4 0

Answer:

Step-by-step explanation:

7x + 5y = -13 ....multiply by 2

-2x - 7y = 26 .....multiply by 7

-------------------------

14x + 10y = -26 (result of multiplying by 2)

-14x - 49y = 182 (result of multiplying by 7)

-----------------------add

-39y = 156

y = -156/39

y = -4

7x + 5y = -13

7x + 5(-4) = -13

7x - 20 = -13

7x = -13 + 20

7x = 7

x = 7/7

x = 1

check...

-2x = 7y + 26

-2(1) = 7(-4) + 26

-2 = -28 + 26

-2 = -2 (correct)...it checks out

answer is : x = 1 and y = -4 or (1,-4)

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Answer:

$\lim _{x\to 2}\:\frac{x-2}{x^2-2}\\\\ \lim _{x\to 11}\:\frac{x^2+6x-187}{x^2+3x-154}\\\\ \lim _{x\to \frac{5}{2}}\left\frac{2x^2+x-15}{2x-5}\right$

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c) $\lim _{x\to 2}\:\frac{x-2}{x^2-2}=\frac{2-2}{\left(2\right)^2-2}=\frac{0}{4-2}=0$

d) $\lim _{x\to 11}\:\frac{x^2+6x-187}{x^2+3x-154}=\lim _{x\to 11}\:\frac{\left(x-11\right)\left(x+17\right)}{\left(x-11\right)\left(x+14\right)}=\lim _{x\to 11}\:\frac{\left(x+17\right)}{\left(x+14\right)}=\frac{11+17}{11+14}=\frac{28}{25}$

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Answer:

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