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Vitek1552 [10]
3 years ago
9

Solve: |4x+3/5|=1/3 and |4x+3/5|=-1/3

Mathematics
1 answer:
AVprozaik [17]3 years ago
5 0

Step-by-step explanation:

Bro please tell that it is 14x Or 4x and 3/51 or 3/5

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4 years ago
Whats 3^2 in standard form?
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3*3 = 9

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7 0
3 years ago
Give two ways to write each algebraic expression in words. 4+×
KATRIN_1 [288]

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4 0
3 years ago
The function g(x)=-(x)^2+5. The function f(x)=-g(x+2).
Vitek1552 [10]
Short Answer f(x) down 5 units, left 2 units and right side up from g(x)
Step One

Find out what -g(x+2) is.
There are two steps to this. The first is to deal with the minus sign
(g(x)) = - x^2 + 5. Be very careful what you do next. 
Put brackets around both terms on the right.
g(x) = (-x^2 + 5) Now put the minus sign in front of g(x) and another one in front of the brackets.
-g(x) = - (-x^2 + 5) Remove the brackets.
-g(x) = x^2 - 5 

<em>Result</em>
So far g(x) moves down 5 units and opens upward. 

Step Two
The second step is to see what the x + 2 does.
-g(x + 2) = (x + 2)^2 - 5

The final result is that the graph opens upward, moves left 2 spaces and down 5.

There is a graph enclosed to show you the key steps.
The red graph is g(x) = x^2 - 5
The blue graph is g(x+2) = (x+2)^2 - 5

5 0
3 years ago
My quadrilateral has no lines of symmetry but it does have rotation symmetry. what is it?”
Elina [12.6K]

We have to identify the quadrilateral with no line of symmetry and have rotational symmetry.

Line of symmetry  is the imaginary line which divide the given quadrilateral in two equal halves.

Rotational symmetry is when an object is rotated around a center point (turned) a number of degrees and the object appear the same.

Parallelogram is a quadrilateral which has no line of symmetry as we can not draw any imaginary line which divides the parallelogram in two equal halves.

But Parallelogram has rotational symmetry as when a parallelogram is rotated around a center point (turned) a number of degrees and parallelogram appear the same.

Hence, Parallelogram is the quadrilateral.

8 0
4 years ago
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