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Sindrei [870]
3 years ago
6

Help please!!!!!!!!!!!!!!!!!

Mathematics
1 answer:
Irina-Kira [14]3 years ago
7 0

Answer:

Step-by-step explanation:

4x=2(x+6)  

4x=2x+6

2x=6

x=3

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Let R={0, 1, 2, 3} be the range of h(x) = x - 7. The domain of h inverse is_____.
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{-7,-6,-5,-4}

Step-by-step explanation:

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or look at it this way:

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Step-by-step explanation:

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Alex Ar [27]

NOTES:

  • squared (²) means multiply that number by itself 2 times
  • cubed (³) means multiply that number by itself 3 times
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Answer: (C) 41

<u>Step-by-step explanation:</u>

\quad 6^2+\sqrt[3]{125} \\= 6 \cdot 6+\sqrt[3]{5\cdot 5 \cdot 5}\\= 36 + 5\\= 41

***************************************************************************************

Answer: (C) 10

<u>Step-by-step explanation:</u>

   \bigg(\dfrac{7}{3}\times \sqrt[3]{27}-2\bigg)\times \dfrac{1}{5} + \sqrt{81}

=\bigg(\dfrac{7}{3}\times \sqrt[3]{3\cdot 3 \cdot 3}-2\bigg)\times \dfrac{1}{5} + \sqrt{9\cdot 9}

=\bigg(\dfrac{7}{3}\times3-2\bigg)\times \dfrac{1}{5}+9

=(7 - 2)\times \dfrac{1}{5}+9

=5 \times \dfrac{1}{5}+ 9

= 1 + 9

= 10

***************************************************************************************

8² = 8 · 8 = 64                                     11² = 11 · 11 = 121

5³ = 5 · 5 · 5 = 125                               3³ = 3 · 3 · 3 = 27

\sqrt{1600}=\sqrt{40\cdot 40}=40                       \sqrt[3]{64}=\sqrt[3]{4\cdot 4\cdot 4}=4

\sqrt{144}=\sqrt{12\cdot 12}=12                            \sqrt[3]{8000}=\sqrt[3]{20\cdot 20\cdot 20}=20

3 0
3 years ago
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