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2 years ago

Someone plz help me giving brainliest

Mathematics

1 answer:

Alexeev081 [22]2 years ago

7 0

Answer:

8, 16, 26, 52, 62, 124, 134, 268, 278, 556

PLEASE MARK ME BRAINLIEST IF THIS HELPED!

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Please I need help please asap

Amanda [17]

I think the answer is D

6 0

2 years ago

17/24 turned into a decimal

madreJ [45]

Answer:

Your answer would be 0.7083

5 0

3 years ago

Read 2 more answers

I'm having trouble with #2. I've got it down to the part where it would be the integral of 5cos^3(pheta)/sin(pheta). I'm not sur

Butoxors [25]

$\displaystyle\int\frac{\sqrt{25-x^2}}x\,\mathrm dx$

Setting $x=5\sin\theta$ , you have $\mathrm dx=5\cos\theta\,\mathrm d\theta$ . Then the integral becomes

$\displaystyle\int\frac{\sqrt{25-(5\sin\theta)^2}}{5\sin\theta}5\cos\theta\,\mathrm d\theta$
$\displaystyle\int\sqrt{25-25\sin^2\theta}\dfrac{\cos\theta}{\sin\theta}\,\mathrm d\theta$
$\displaystyle5\int\sqrt{1-\sin^2\theta}\dfrac{\cos\theta}{\sin\theta}\,\mathrm d\theta$
$\displaystyle5\int\sqrt{\cos^2\theta}\dfrac{\cos\theta}{\sin\theta}\,\mathrm d\theta$

Now, $\sqrt{x^2}=|x|$ in general. But since we want our substitution $x=5\sin\theta$ to be invertible, we are tacitly assuming that we're working over a restricted domain. In particular, this means $\theta=\sin^{-1}\dfrac x5$ , which implies that $\left|\dfrac x5\right|\le1$ , or equivalently that $|\theta|\le\dfrac\pi2$ . Over this domain, $\cos\theta\ge0$ , so $\sqrt{\cos^2\theta}=|\cos\theta|=\cos\theta$ .

Long story short, this allows us to go from

$\displaystyle5\int\sqrt{\cos^2\theta}\dfrac{\cos\theta}{\sin\theta}\,\mathrm d\theta$

to

$\displaystyle5\int\cos\theta\dfrac{\cos\theta}{\sin\theta}\,\mathrm d\theta$
$\displaystyle5\int\dfrac{\cos^2\theta}{\sin\theta}\,\mathrm d\theta$

Computing the remaining integral isn't difficult. Expand the numerator with the Pythagorean identity to get

$\dfrac{\cos^2\theta}{\sin\theta}=\dfrac{1-\sin^2\theta}{\sin\theta}=\csc\theta-\sin\theta$

Then integrate term-by-term to get

$\displaystyle5\left(\int\csc\theta\,\mathrm d\theta-\int\sin\theta\,\mathrm d\theta\right)$
$=-5\ln|\csc\theta+\cot\theta|+\cos\theta+C$

Now undo the substitution to get the antiderivative back in terms of $x$ .

$=-5\ln\left|\csc\left(\sin^{-1}\dfrac x5\right)+\cot\left(\sin^{-1}\dfrac x5\right)\right|+\cos\left(\sin^{-1}\dfrac x5\right)+C$

and using basic trigonometric properties (e.g. Pythagorean theorem) this reduces to

$=-5\ln\left|\dfrac{5+\sqrt{25-x^2}}x\right|+\sqrt{25-x^2}+C$

4 0

2 years ago

Read 2 more answers

Solve #3 Find the length of the missing side.a) A right triangle has a side length 2.4 cm and 6.5 cm. What is the length of the

Snezhnost [94]

Answer:

A) ≈ 6.93

B) ≈ 0.02

Step-by-step explanation:

Formula : a² + b² = c²

2.4² + 6.5² = c²

5.76 + 42.25 = c²

c = √48.01

c ≈ 6.93

Formula = c² - a² = b²

1/3² - 1/4² = b²

1/9 - 1/16 = b²

b = √7/144

b ≈ 0.02

If my answer is incorrect, pls correct me!

If you like my answer and explanation, mark me as brainliest!

-Chetan K

3 0

2 years ago

Read 2 more answers

The line passing through which two points is parallel to the line x - 2y = 16?

Naddika [18.5K]

Answer:

E) -4,7 and -2,8

Step-by-step explanation:

parallel lines have same slope

x - 2y = 16

y = 1/2 x -8 slope: 1/2

E. slope = Δy / Δx = (8-7) / (-2 - -4) = 1/2

5 0

2 years ago