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worty [1.4K]
3 years ago
7

The question is number 16

Mathematics
1 answer:
stellarik [79]3 years ago
3 0
18×7+5 is your answer. The answer for the problem is 18×7=126. 

126+5=131. 
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In a carnival drawing, a green ticket wins $1, a yellow ticket wins $5, and a blue ticket wins $10. There are 100 green tickets,
Evgesh-ka [11]

The odds in favor of winning $5 or more is 3 : 13

<h3>What are the odds in favor of winning $5 or more?</h3>

The odds of winning $5 or more can be determined by finding the ratio of the total value of tickets that have a value of $5 or greater to the total value of tickets.

Total number  of the tickets that have a value of $5 or more = 25 + 5 = 30

Total number of ticket  = 25 + 5 + 100 = 130

Ratio : 30 : 130

3 ; 13

To learn more about ratios, please check: brainly.com/question/9194979

#SPJ1

5 0
2 years ago
A confidence interval (CI) is desired for the true average stray-load loss u (watts) for a certain type of induction motor when
Genrish500 [490]

Answer:

A) CI = (57.12 , 59.48)

B) CI = (57.71 , 58.89)

C) CI = (57.53 , 59.07)

D) n = 239.63

Step-by-step explanation:

a)

given data:

mean, \bar X = 58.3

standard deviation, σ = 3

sample size, n = 25Given CI level is 95%, hence α = 1 - 0.95 = 0.05

α/2 = 0.05/2 = 0.025,

Zc = Z(α/2) = 1.96

ME = Zc * σ \sqrt{n}

ME = 1.96 * 3 \sqrt{25}

ME = 1.18

CI = (\bar X - Zc * s\sqrt{n}  , \barX + Zc * s\sqrt{n})

CI = (58.3 - 1.96 * 3\sqrt{25} , 58.3 + 1.96 * 3\sqrt{25})

CI = (57.12 , 59.48)

b)

Given data:

mean, \bar X = 58.3

standard deviation, σ = 3

sample size, n = 100

Given CI level is 95%, hence α = 1 - 0.95 = 0.05

α/2 = 0.05/2 = 0.025, Zc = Z(α/2) = 1.96

ME = zc * σ \sqrt{n}

ME = 1.96 * 3\sqrt{100}

ME = 0.59

CI = (\bar X - Zc * s\sqrt{n}  , \barX + Zc * s\sqrt{n})

CI = (58.3 - 1.96 * 3\sqrt{100} , 58.3 + 1.96 * 3\sqrt{100})

CI = (57.71 , 58.89)

c)

sample mean, \bar X = 58.3

sample standard deviation, σ = 3

sample size, n = 100

Given CI level is 99%, hence α = 1 - 0.99 = 0.01

α/2 = 0.01/2 = 0.005, Zc = Z(α/2) = 2.58

ME = Zc * σ \sqrt{n}

ME = 2.58 * 3\sqrt{100}

ME = 0.77

CI = (\bar X - Zc * s\sqrt{n}  , \barX + Zc * s\sqrt{n})

CI = (58.3 - 2.58 * 3\sqrt{100} , 58.3 + 2.58 * 3/\sqrt{100}

CI = (57.53 , 59.07)

D)

Given data:

Significance Level, α = 0.01,

Margin or Error, E = 0.5,

σ = 3

The critical value for α = 0.01 is 2.58.

for calculating population mean we used

n \geq (zc *σ/E)^2

n = (2.58 * 3/0.5)^2

n = 239.63

7 0
3 years ago
A car is driving towards home at 0.5 miles per minute. If the car is 4 miles from home at t=0 , which of the following can repre
Lostsunrise [7]

Answer:

the answer is D

7 0
3 years ago
Which of the following are congruence transformations? Check all that apply.. A. Translating. B. Reflecting. C. Rotating. D. Shr
Temka [501]
Congruence transformations are:
A ) Translating,
B ) Reflecting,
C ) Rotating.
7 0
3 years ago
Kristin decides to spend at most $50 for a birthday dinner at a restaurant, including a 15% tip.,
Dmitry [639]
0.15x + x <(or equal to) 50
Where x is the meal's cost (no tip included)

50 - 15% = 42.5.
x >(or equal to) 42.50.

(nothing is copied content, I copy pasted a number into the right position, feel free to check it mods)
7 0
4 years ago
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