Question

Prove that5E%7B2%7D%20%5Ctimes%20%20%7B2%7D%5E%7B0%7D%20%20%20%3D%2017" id="TexFormula1" title=" {2}^{3} \times {3}^{0} + {3}^{2} \times {2}^{0} = 17" alt=" {2}^{3} \times {3}^{0} + {3}^{2} \times {2}^{0} = 17" align="absmiddle" class="latex-formula">
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Answer 1

Answer:

Step-by-step explanation:

Anything raise to the power zero is 1

Therefore,

               $LHS\\\\ =2^3 \times 3^0 + 3^2 \times 2^0\\\\8 \times 1 + 9 \times 1 \\\\17$

LHS = RHS

Hence Proved