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3 years ago

Please help ill give brainliest

Mathematics

2 answers:

mezya [45]3 years ago

8 0

The correct answer is 6 ;)

boyakko [2]3 years ago

7 0

Correct answer is 6... NOT 7...

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Determine the quotient of 1 and 2 over 3 divided by 4 over 5. 1 and 1 over 3 1 and 8 over 15 2 and 1 over 12 2 and 5 over 6

Molodets [167]

Use a calculator my friend.

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3 years ago

Kate used 2/5 of a pound of sugar to bake cookies. She used another 3/4 of a pound of flour for the cookies. How many pounds of

stepan [7]

Answer:

c. 1 3/20

Step-by-step explanation:

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3 years ago

A retail outlet offers a retention bonus for each shopping season an employee remains with the company. Samuel's starting pay is

miv72 [106K]

Answer:

Samuel's hourly rate after n seasons with the company is f(n)= 12.50 + 0.35*n. After 18 seasons with the company, Samuel's hourly rate will be 18.8 $ /hr.

Step-by-step explanation:

You know that Samuel's starting pay is $12.50/hr and for each season Samuel remains with the company, he receives a $0.35/hr raise.

Samuel's hourly rate after n seasons at the company will then be:

f(n)= 12.50 + 0.35*n

To determine the hourly rate after 18 seasons, you must replace the value n with 18:

f(18)= 12.50 + 0.35*18

Solving you get:

f(18)= 12.50 + 6.3

f(18)= 18.8

<u><em>Samuel's hourly rate after n seasons with the company is f(n)= 12.50 + 0.35*n. After 18 seasons with the company, Samuel's hourly rate will be 18.8 $ /hr. </em></u>

6 0

3 years ago

What do you think the value of represents in the function? How can you predict what the graph of a quadrati function will look l

allochka39001 [22]

Answer:

Step-by-step explanation:

Parts of the question are missing.

y = a(x-h)² + k is a vertical parabola.

If a is positive, the parabola opens upwards.

If a is negative, the parabola opens downwards.

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7 0

2 years ago

Suppose the sediment density (g/cm) of a randomly selected specimen from a certain region is normally distributed with mean 2.65

erma4kov [3.2K]

Answer:

Probability that the sample average is at most 3.00 = 0.98030

Probability that the sample average is between 2.65 and 3.00 = 0.4803

Step-by-step explanation:

We are given that the sediment density (g/cm) of a randomly selected specimen from a certain region is normally distributed with mean 2.65 and standard deviation 0.85.

Also, a random sample of 25 specimens is selected.

Let X bar = Sample average sediment density

The z score probability distribution for sample average is given by;

Z = $\frac{Xbar-\mu}{\frac{\sigma}{\sqrt{n} } }$ ~ N(0,1)

where, $\mu$ = population mean = 2.65

$\sigma$ = standard deviation = 0.85

n = sample size = 25

(a) Probability that the sample average sediment density is at most 3.00 is given by = P( X bar <= 3.00)

P(X bar <= 3) = P( $\frac{Xbar-\mu}{\frac{\sigma}{\sqrt{n} } }$ <= $\frac{3-2.65}{\frac{0.85}{\sqrt{25} } }$ ) = P(Z <= 2.06) = 0.98030

(b) Probability that sample average sediment density is between 2.65 and 3.00 is given by = P(2.65 < X bar < 3.00) = P(X bar < 3) - P(X bar <= 2.65)

P(X bar < 3) = P( $\frac{Xbar-\mu}{\frac{\sigma}{\sqrt{n} } }$ < $\frac{3-2.65}{\frac{0.85}{\sqrt{25} } }$ ) = P(Z < 2.06) = 0.98030

P(X bar <= 2.65) = P( $\frac{Xbar-\mu}{\frac{\sigma}{\sqrt{n} } }$ <= $\frac{2.65-2.65}{\frac{0.85}{\sqrt{25} } }$ ) = P(Z <= 0) = 0.5

Therefore, P(2.65 < X bar < 3) = 0.98030 - 0.5 = 0.4803 .

8 0

4 years ago