A car passes a landmark on a highway traveling at a constant rate of 45 kilometers per hour.
Let t be the time taken by second car
So t+1 is the time taken by first car
Distance = speed * time
Distance traveled by first car = 45 * (t+1)
second car passes the same landmark traveling in the same direction at 65 kilometers per hour
Distance traveled by second car = 65 * (t)
When second car overtakes the first car then their distance are same
65 t = 45(t+1)
65t = 45t + 45
Subtract 45 t from both sides
20t = 45
Divide both sides by 20
so
It took 2.25 hours for the second car to overtake first car
Answer:
160
Step-by-step explanation:
the length betwenn side to side woukd be 160
0.59 = (1 - 0.000125)^^x where x = number of years of decay
ln 0.59 = x ln(0.999875)
x = 4221 to nearest year
Answer:
y = -4x+15
Step-by-step explanation:
y=x/4+5 may be presented as y = 1/4 x + 5, where a=1/4, b=5
swapping numerator and denominator and inserting an opposite sign in a=1/4, we have:
1/4 --------> 4/1 -------> -4/1 = -4
y = -4x+n
Point (2,7) means that x=2, y=7 substitute it to the equation y=-4x+n, calculate "n":
7=-4*2+n ------> 7=-8+n -------> 7+8 = n -------> 15=n
substituting n=15 to the equation y=-4x+n, we get finally y=-4x+15