Two lines are perpendicular if and only if the product of their slopes is - 1.
So, you just need to find the slope of each line and find out the product of their slopes.
I will do one example for you.
L1: y = 3x + 5
L2: y = - 3x + 14
L3: y = -x/3 + 14
The slope of a line is the coefficient of the x.
So the slopes are:
L1: slope 3
L2: slope -3
L3: slope -1/3
So now multiply the slopes of each pair of lines:
L1 and L2: 3 * (-3) = - 9 => No, they are not perpendicular
L2 and L3: (-3) * (-1/3) = 1 => No, they are not perpendicular
L1 and L3: (3) * (-1/3) = -1 => Yes, they are penpendicular.
Answer:
x = -7
Step-by-step explanation:
2x+3 = x-4
2x-x = -4-3
x = -7
hope it helps ☺️
Answer:
3/2
Sorry for the bad handwriting.
T= sqrt(5/wc)
remove ( )
T= 5sqrt/wc
multiply by wc
Twc=5sqrt
divide by Tc
W= 5sqrt/cT
hope this helps
