Answer:
Step-by-step explanation:
F(x) = x² - 2x + 1
= (x - 1)²
By comparing this equation with the vertex form of the quadratic equation,
y = (x - h)² + k
Here, (h, k) is the vertex
Vertex of the parabola → (1, 0)
x-intercepts → (x - 1)² = 0
x = 1
y-intercepts → y = (0 - 1)²
y = 1
Now we can draw the graph of the given function,
From this graph,
As x → 0,
f(0) = (0 - 1)²
= 1
Since,
Therefore, given function is continuous at x = 0.
Part A)
Recall that:
1) The function represented by the graph of the function f(x) translated vertically n units up and horizontally m units left is:
2) The function represented by the graph of the function f(x) reflected over the x-axis is:
Now, notice that g(x) is the function f(x) reflected over the x-axis and then translated vertically 6 units up and horizontally 4 units left.
Answer Part A:
Options B, C, and D.
Part B) To graph g(x) we will reflect the graph of f(x) over the x-axis and then we will translate it vertically 6 units up and horizontally 4 units left.
We know that the graph of f(x)=|x| is:
The above graph reflected over the x-axis is:
Finally, the above graph translated vertically 6 units up and horizontally 4 units left is:
Answer part B:
