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Olegator [25]
3 years ago
6

Write a question about Teresa and the sock puppets for which the answer is 3 explain the answer

Mathematics
2 answers:
Viefleur [7K]3 years ago
6 0

Answer:

<h2>What's the quotient between yellow sock puppets and blue sock puppets.</h2>

Step-by-step explanation:

Teresa has three blue sock puppets and 6 yellow sock puppets. What's the quotient between yellow sock puppets and blue sock puppets.

To answer this question, we just have to divide all 6 yellow suck puppets by all three blue sock puppets

\frac{6}{3}=2

Therefore, the quotient between yellow sock puppets and blue sock puppets is 2

disa [49]3 years ago
4 0
I dont know if this will help you...teresa has 1 bag with 3 sock puppets, she uses them to entertain her classmates at school.how much sock puppets does she have?answer:she has 3 because she has 1 bag in which contain 3 sock puppets so 1×3=3.
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8 0
2 years ago
If I get 100 dollars a week for four months how much will I have
Gre4nikov [31]

Answer:

1600 dollars

Step-by-step explanation:

Find out how much you earn a month

1 month = 4 weeks

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4 0
3 years ago
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Mary’s pet turtle Waze mary’s pet turtle Weighs 4.094 pounds. How is this number written in word form?
svp [43]
Four and ninety four thousandths. You're welcome!
6 0
2 years ago
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Explain how you know 21/30 is greater than 2/3
Luba_88 [7]
Simple.

to figure out if they are either: equal, greater, or smaller...

First, find a common denominator...

\frac{21}{30}

and

\frac{2}{3} * \frac{10}{10} = \frac{20}{30}

Now, we can obviously make the assumption that \frac{21}{30} is greater than \frac{20}{30}.

Thus, your answer. 

3 0
3 years ago
Read 2 more answers
I don’t know how to do this
stich3 [128]

To check for continuity at the edges of each piece, you need to consider the limit as x approaches the edges. For example,

g(x)=\begin{cases}2x+5&\text{for }x\le-3\\x^2-10&\text{for }x>-3\end{cases}

has two pieces, 2x+5 and x^2-10, both of which are continuous by themselves on the provided intervals. In order for g to be continuous everywhere, we need to have

\displaystyle\lim_{x\to-3^-}g(x)=\lim_{x\to-3^+}g(x)=g(-3)

By definition of g, we have g(-3)=2(-3)+5=-1, and the limits are

\displaystyle\lim_{x\to-3^-}g(x)=\lim_{x\to-3}(2x+5)=-1

\displaystyle\lim_{x\to-3^+}g(x)=\lim_{x\to-3}(x^2-10)=-1

The limits match, so g is continuous.

For the others: Each of the individual pieces of f,h are continuous functions on their domains, so you just need to check the value of each piece at the edge of each subinterval.

4 0
3 years ago
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