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BaLLatris [955]
3 years ago
14

3. The matrices show the enrollment of boys and girls on the basketball, lacrosse, and soccer teams in two towns. Town A Town B

Boys Girls Boys Girls Basketball[84 76] Basketball [94 70] Lacrosse [72 88] Lacrosse [88 89] Soccer [96 100] Soccer [100 110] A. If we let matrix A be the matrix for Town A, what is the element a21, and what does it represent? B. If we let matrix B be the matrix for Town B, what is the address of the element that represents the number of girls enrolled in soccer in Town B? C. What is the matrix that results when you subtract matrix A from matrix B? D. Name the matrix you found in Part C matrix C. What is element c12, and what information does it tell you about the number of girls enrolled in basketball in Town B compared with Town A? E. What is the matrix that shows the enrollment in Town A after a 25% increase in enrollment in all sports and in both genders? (Hint: Find 1.25A.)
Mathematics
1 answer:
bazaltina [42]3 years ago
8 0
(a). The element a₂₁ is the number of boys enrolled in Lacrosse.

(b). The address is a₁₂.

(c). [196   174]
      [136   169]
      [214    242]

(d). The matrix represents the number of boys and girls from towns A and B enrolled in different sports classes.

(e). 1.125 A = [108   90  ]
                       [72     99  ]
                       [117   135]<span />
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An arched drainage culvert can be modelled by the function:
Zanzabum

Substitute 136.5 for y.

136.5=\frac{x(191-x)}{60}

8190=x(191-x)

8190=191x-x^{2}

x^{2} -191x+8190=0

Compare this equation with ax^{2} +bx+c=0

a = 1, b = - 191, c = 8190

x=\frac{-b+\sqrt{b^{2}-4ac } }{2} or

x=\frac{-b-\sqrt{b^{2}-4ac } }{2}

x=\frac{191+\sqrt{191^{2}-4(1)(8190) } }{2} or

x=\frac{191-\sqrt{191^{2}-4(1)(8190) } }{2}

x=\frac{191+\sqrt{36481-32760 } }{2} or

x=\frac{191-\sqrt{36481-32760 } }{2}

x=\frac{191+\sqrt{3721 } }{2} or

x=\frac{191-\sqrt{3721 } }{2}

x=\frac{191+61}{2} or

x=\frac{191-61}{2}

x=\frac{252}{2} or

x=\frac{130}{2}

x = 126 or x = 65

Hence, the points on the curve are (65, 136.5) and (126, 136.5).

The width of the air space is the distance between these points.

Width = \sqrt{(x_{2}- x_{1})^{2} +( y_{2}- y_{1}) ^{2}

= \sqrt{(126- 65)^{2} +(136.5-136.5) ^{2}

= 126 - 65

= 61

Hence, width of the air space is 61m.



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3 years ago
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