A. -4
b. -6
c. 0 if the expression is 6 - 8 + 2 but if it is 6 - 8 ÷ 2 = 2
d. -2.1
Answer:
see explanation
Step-by-step explanation:
Using the Sine rule in all 3 questions
(1)
=
, substitute values , firstly calculating ∠ B
[ ∠ B = 180° - (78 + 49)° = 180° - 127° = 53° ]
=
( cross- multiply )
a sin53° = 18 sin78° ( divide both sides by sin53° )
a =
≈ 22.0 ( to the nearest tenth )
(3)
=
, substitute values
=
( cross- multiply )
45 sinC = 35 sin134° ( divide both sides by 35 )
sinC =
, then
∠ C =
(
) ≈ 34.0° ( to the nearest tenth )
(5)
Calculate the measure of ∠ B
∠ B = 180° - (38 + 92)° = 180° - 130° = 50°
=
, substitute values
=
( cross- multiply )
BC sin50° = 10 sin38° ( divide both sides by sin50° )
BC =
≈ 8.0 ( to the nearest tenth )
(Refer to the diagram in the attached photo.)
In this diagram there is defined two
Sides and an
Angle in between (SAS).
Notice how there are two loose endpoints in the diagram. A single line segment can be drawn connecting the endpoints, forming a unique triangle.
If the original diagram is transformed, the dimensions and angles formed by the third line segment remains the same relative to the first two.
Therefore, if two triangles have the same SAS configuration, then they are congruent.
Answer:
x=60°
Step-by-step explanation:
Let's say the point where angle x is, be K
Because ABCD and PQRS are paralelograms,
∡PSR = ∡PQR =130°
and
∡DAB=∡DCB=70°
and by angles between parallels
∡SPQ + ∡PQR = 180°
∡SPQ + 130° = 180°
∡SPQ = 50°
by angles opposite by vertex
∡PKC = ∡BKQ = x
So in triangle PKC the sum of all angles must add up to 180°
so
∡SPQ + ∡PKC + ∡DCB = 180
50 + x + 70 = 180
x = 60