since the cone's diameter is 6, its radius must be 3 then.
![\bf \textit{total surface area of a cone}\\\\ SA=\pi rs+\pi r^2~~ \begin{cases} r=&radius\\ s=&slant~height\\ \cline{1-2} r=&3\\ s=&5 \end{cases}\implies SA=\pi (3)(5)+\pi (3)^2 \\\\\\ SA=15\pi +9\pi \implies SA=24\pi \implies SA\approx 75.398](https://tex.z-dn.net/?f=%5Cbf%20%5Ctextit%7Btotal%20surface%20area%20of%20a%20cone%7D%5C%5C%5C%5C%20SA%3D%5Cpi%20rs%2B%5Cpi%20r%5E2~~%20%5Cbegin%7Bcases%7D%20r%3D%26radius%5C%5C%20s%3D%26slant~height%5C%5C%20%5Ccline%7B1-2%7D%20r%3D%263%5C%5C%20s%3D%265%20%5Cend%7Bcases%7D%5Cimplies%20SA%3D%5Cpi%20%283%29%285%29%2B%5Cpi%20%283%29%5E2%20%5C%5C%5C%5C%5C%5C%20SA%3D15%5Cpi%20%2B9%5Cpi%20%5Cimplies%20SA%3D24%5Cpi%20%5Cimplies%20SA%5Capprox%2075.398)
Answer:
![9x + x - 4x = 6x](https://tex.z-dn.net/?f=9x%20%2B%20x%20-%204x%20%3D%206x)
they're all like terms so we just add and subtract
Answer:
volume of the hemisphere ≈13.3 m³
Step-by-step explanation:
To find the volume of the hemisphere, we will follow the steps below;
volume of a hemisphere = volume of a sphere/2
=
πr³ /2
=
πr³
from the question given, the diameter is 3.7 m, but diameter = 2×radius
radius = diameter /2 = 3.7/2 =1.85 m
π is a constant = 3.14
volume of a hemisphere =
πr³
≈
×3.14 ×1.85³
≈13.3 m³
Therefore, volume of the hemisphere ≈13.3 m³
The length is 7 and the width is 6 because 6x3=18 , 18-7=11 and 6x7=42