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natali 33 [55]
3 years ago
14

A larger number is twelve morethan a smaller. Their sum is84. Find the numbers.​

Mathematics
2 answers:
Svetllana [295]3 years ago
6 0

Answer:

  • The smaller number  ⇒ y = 36
  • The larger number ⇒ x = y + 12 = 36 + 12 = 48

Step-by-step explanation:

  • Let the larger number be = x
  • Let the smaller number be = y

As the larger number is twelve more  than a smaller, so

x = y + 12

As the sum of larger and smaller numbers is 84, so

x + y = 84

now substituting x = y + 12 in th equation x + y = 84

x + y = 84

(y + 12) + y = 84

2y + 12 = 84

subtract 12 from both sides

2y + 12 - 12 = 84 - 12

2y = 72

divide both sides by 2

2y/2 = 72/2

y = 36

Thus,

  • The smaller number  ⇒ y = 36
  • The larger number ⇒ x = y + 12 = 36 + 12 = 48
Elenna [48]3 years ago
4 0

Answer:  bigger number is 48 and smaller number is 36

Step-by-step explanation:

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Step-by-step explanation:

1.

Base =16 ft and Height = 18 ft

Area of the parallelogram = base × height

                                       =16× 18 square units

                                       = 288 square units

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Base = 9 m and height = 5 m

Area of the parallelogram = base × height

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3 .

Height = 4 in and parallel sides are 12 in and 5 in

Area of the  trapezoid =\frac {1}{2} \times( {\textrm{sum of the parallel sides}}) \times height

                            =\frac{1}{2} \times (12+5) \times 4 square in.

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Height = 2 ft  and parallel sides are 2 ft and 6 ft

Area of the trapezoid =\frac {1}{2} \times( {\textrm{sum of the parallel sides}}) \times height

                              =\frac{1}{2} \times (2+6) \times 2 square ft

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Diagonals are 6 cm and 9 cm.

Area of the rhombus = \frac{1}{2}\times {\textrm{product of diagonals}

                               =\frac{1}{2 } \times 6\times 9 square cm

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Area of the rhombus = \frac{1}{2}\times {\textrm{product of diagonals}

                               =\frac{1}{2 } \times 12\times 18 square in

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The area of the desktop is = (30 × 40 ) square in

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The area of the rhombus = \frac {1}{2} \times 14 \times 12 cm^2

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Area of the trapezoid =\frac {1}{2} \times( {\textrm{sum of the parallel sides}}) \times height

                                    = \frac{1}{2} \times (24+16) \times 12 square ft

                                     = 240 square ft

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