I think its the third one
x^2 - 3x -28 ≥ 0
factor
(x-7) (x+4) ≥ 0
x=7 x=-4
we have three regions where the answers can lie
x<-4 between -4 and 7 and x>7
pick a point and see if it works
x=-10
(-10-7) (-10+4) ≥ 0
negative * negative is greater than 0 so this is a solution x< -4
x=0
(0-7) (+4) ≥ 0
negative * positive is less than 0 so this is not a solution
x=10
(10-7) (10+4) ≥ 0
positive * positive is greater than 0 so this is a solution x>7
We have two regions that work
x<-4 and x>7
= a^21b^24c^10
use the product rules for each set of () then multiply them together. when multiplying variables with exponents you just add them together like for a^3 * a^5 = a^8. (a^3 b^12 c^2)^2 = (a^6 b^24 c^4)
I'm sorry but maybe you wrote this wrong. If Wendy has 1 pint of milk and only needs 1 pint of milk, then she has exactly the amount she needs.
