The mass of cesium left afer 120 years if the original mass of cesium is 8640 with an half-life of 30 years, is 540 grams.
<h3>What is half-life?</h3>
This can be defined as the time taken for half the amount of a radioactive substance to decay.
To calculate the amount of cesium left after 120 years, we use the formua below.
Formula:
- R' = R/(
)............. Equation 1
Where:
- R = Original amount of Cesium
- R' = New amount of cesium
- T = Total time
- t = Half-life
From the question,
Given:
- R = 8640
- T = 120 years
- t = 30 years
Substitute these values into equation 1
- R' = 8640/(
) - R' = 8640/

- R' = 8640/16
- R' = 540 grams.
Hence, The mass of cesium left afer 120 years is 540 grams.
Learn more about half-life here: brainly.com/question/25750315
Answer:
10
Step-by-step explanation:
How many times greater is the value of 4 in 547 than the value of the 4 and 84?
547: 500 + 40 + 7
5 is in the hundreds place
4 is in the tens place
7 is in the ones place
84: 80 + 4
8 is in the tens place
4 is in the ones place
The value of 4 in 547 is 10 times greater than the value of 4 in 84.
Since the 4 in 547 is in the tens place, while the 4 in 84 is in the ones place.
Also, 4 * 10 = 40
Hope this helps!
Answer: y = -x + 7
Step-by-step explanation:
The slope is
, so we know the equation is of the form
.
Substituting in the coordinates (1,6) to find b,

Thus, the equation is y = -x + 7
Answer:
22.86
Step-by-step explanation:
2.54 x 9 will give you the answer.