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3 years ago

6

What is the equation in slope-intercept form of the line that passes through the point (6, 1) and is parallel to the line repres

ented by
y = -3x + 2?
Enter your answer by filling in the boxes.

1 answer:

sweet-ann [11.9K]3 years ago

8 0

The answer would be 6x-3

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An old railroad car was able to haul one days worth of coal in 15 hours the new railroad car only takes 10 hours because of high

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Step-by-step explanation:

Old Railroad Car:

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New Railroad Car:

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3 years ago

What is the fraction form of the following decimal expansion? 0.3 repeating?

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3 years ago

Can someone PLZZZZ HELP!!!!

swat32

Answer:

The solution is:

Part A. $\sqrt{5}^{\frac{7k}{3}})$ which is sqrt(5)^7k/3[/tex]

Part B. k = 18/7

Step-by-step explanation:

Part A.

To solve this part, we're going two use THREE important properties of exponents:

1. $(x^{n})^{m} = x^{nm}$

2. $\frac{x^{n}}{x^{m}} = x^{n-m}$

3. $\sqrt[n]{x^{m}} = x^{\frac{m}{n} }$

Let's work the numerator using the properties 1, 2 and 3:

$(\sqrt{5}^{3} )^{\frac{k}{9} } } = (\sqrt{5}^{3\frac{k}{9}}) = (\sqrt{5}^{\frac{k}{3}})$

Let's work the denominator using the properties 1, 2 and 3:

$(\sqrt{5}^{6} )^{-\frac{k}{3} } } = (\sqrt{5}^{6\frac{k}{3}}) = (\sqrt{5}^(2k))$

Now dividing the numerator by the denominator:

$\sqrt{5}^{\frac{k}{3}-(-2k)})=\sqrt{5}^{\frac{7k}{3}})$

Part B

if $5^{\frac{3}{2} } 5^{\frac{3}{2}} = \sqrt{5}^{\frac{7k}{3}})$

Then:

$5^{3} = 5^{\frac{7k}{6}})$

So $\frac{7k}{6}} = 3$

Solving for k, we have:

k = 18/7

7 0

3 years ago