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olya-2409 [2.1K]
2 years ago
13

Please help me with this question:

Mathematics
2 answers:
ohaa [14]2 years ago
8 0

Answer:

63 = 1 x 63, 3 x 21, or 7 x 9. Factors of 63: 1, 3, 7, 9, 21, 63. Prime factorization: 63 = 3 x 3 x 7, which can also be written 63 = 3² x 7.

Step-by-step explanation:

hope this is right

marissa [1.9K]2 years ago
8 0

Answer:

63= 3*3*7 (3^2*7)

Step-by-step explanation:

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6x +8=5x=4 <br> what is the value of x
Free_Kalibri [48]

Answer:

x = -4/11

Step-by-step explanation:

add the x values.

11x+8=4

subtract 8 from each sides

11x=-4

divide by 11

x=-4/11

8 0
2 years ago
6th-grade math DUE IN 5 MIN
Veseljchak [2.6K]

Answer:

272?

Step-by-step explanation:

10 x 8 = 80

12 x 16 = 192

192 + 80 = 272.

Not sure

3 0
3 years ago
Find the slope of the tangent line to the curve f(x)=e^(x) at (0.4,1.49)
almond37 [142]

Answer:

1.49

Step-by-step explanation:

In order to find the slope of the tangent line to a given equation, and in a given point, we need to:

1. Find the first derivative of the given function.

2. Evaluate the first derivative function in the given point.

1. Let's find the first derivative of the given function:

The original function is f(x)=e^{x}

But remeber that the derivative of  e^{x} is  e^{x}

so, f'(x)=e^{x}

2. Let's evaluate the first derivative function in the given point

The given point is (0.4,1.49) so:

f'(x)=e^{x}

f'(0.4)=e^{0.4}

f'(x)=1.49

Notice that the calculated slope of the tangent line is equal to the y-coordinate of the given point because f'(x)=f(x). In conclusion, the slope of the tangent line is equal to 1.49.

8 0
3 years ago
Which prediction can you make based on this graph?
Colt1911 [192]

Answer:more people will be living in Africa than in Asia sometime around 2120

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
Solve for 5+n/8=4 show your work
Aleks [24]

Answer:

n = -8

Step-by-step explanation:

5+n/8=4

Subtract 5 from each side

5-5+n/8=4-5

n/8 = -1

Multiply each side by 8

n/8 * 8 = -1 *8

n = -8

5 0
3 years ago
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