All categories

3 years ago

I need help this is timed

Mathematics

2 answers:

patriot [66]3 years ago

8 0

6=26

10=38

that should be it

wel3 years ago

8 0

Answer:

The linear equation for this relationship is

y = 3x + 8.

_________

x is the number of people and y is the entrance fee.

_________

2 | 14

4 | 20

6 | 26

8 | 32

10 | 38

30 | 98

38 | 122

You might be interested in

Plz help me I really appreciate it

Serga [27]

Answer:

a = 45°

Step-by-step explanation:

In triangle PSR

PS = RS (Given)

angle SPR = angle SRP (isosceles triangle property)

Let angles SPR and SRP be x

Therefore, 90° + x + x = 180° (angle property)

=> 90° + 2x = 180°

=> 2x = 180° - 90° = 90°

=> 2x = 90°

=> x = 90° ÷ 2 = 45°

=> x = 45°

Hope it helps:)

3 0

2 years ago

The last answer is <1 and <8 help me lol

bagirrra123 [75]

Answer:

huh? no speak english nomore

Step-by-step explanation:

5 0

3 years ago

A student designed this sculpture. Using the dimensions on the sculpture, find the dimensions of each rectangular prism. Then ca

jolli1 [7]

Answer:

Prism Y

$Height = 12in$

$Length = 6in$

$Width = 4in$

$Volume = 288in^3$

Prism Z

$Height = 18in$

$Length =10in$

$Width = 10in$

$Volume = 1800in^3$

$Total = 2088in^3$

Step-by-step explanation:

Given

See attachment for sculpture

Solving (a) The dimension and volume of Y

From the attachment

$Height = 18 - 6$

18 in is the height of Z and 6in represents the length (height) of the unoccupied space by Y

So:

$Height = 12in$

$Length = 16 - 10$

16 in is the total length of the sculpture and 10 in represents the length of Z

So:

$Length = 6in$

$Width = 10 - 6$

10 in is the width of Z and 6in represents the length (width) of the unoccupied space by Y

So:

$Width = 4in$

Hence, the dimension of Y is:

$Height = 12in$

$Length = 6in$

$Width = 4in$

Volume is then calculated as:

$Volume = Length * Width * Height$

$Volume = 12in * 6in * 4in$

$Volume = 288in^3$

Solving (b) The dimension and volume of Z

As identified in (a), the dimensions of Z are:

$Height = 18in$

$Length =10in$

$Width = 10in$

Volume is then calculated as:

$Volume = Length * Width * Height$

$Volume = 18in * 10in * 10in$

$Volume = 1800in^3$

Solving (c): Total volume of the sculpture.

To do this, we simply add up the volumes of Y and Z.

So, we have:

$Total = 288in^3 + 1800in^3$

$Total = 2088in^3$

6 0

3 years ago

The amount of time it takes a bat to eat a frog was recorded for each bat in a random sample of 12 bats. The resulting sample me

spin [16.1K]

Answer: a. CI for the mean: 17.327 < μ < 26.473

b. CI for variance: 29.7532 ≤ $\sigma^{2}$ ≤ 170.9093

Step-by-step explanation:

a. To construct a 95% confidence interval for the mean:

The given data are:

mean = 21.9

s = 7.7

n = 12

df = 12 - 1 = 11

1 - α = 0.05

$\frac{\alpha}{2}$ = 0.025

t-score = $t_{0.025,11}$ = 2.2001

Note: since the sample population is less than 30, it is used a t-score.

The formula for interval:

mean ± $t.\frac{s}{\sqrt{n} }$

Substituing values:

21.9 ± 2.200. $\frac{7.7}{\sqrt{12} }$

21.9 ± 4.573

The interval is: 17.327 < μ < 26.473

b. A 95% confidence interval for the variance:

The given values are:

$s^{2}$ = $7.7^{2}$

$s^{2}$ = 59.29

α = 0.05

$\frac{\alpha}{2}$ = 0.025

$1-\frac{\alpha}{2}$ = 0.975

$\chi^{2}_{0.025,11}$ = 21.92

$\chi^{2}_{0.975,11}$ = 3.816

Note: To find the values for $\chi^{2}_{\alpha/2,n-1}$ and $\chi^{2}_{1-\alpha/2,n-1}$ , look for them at the chi-square table

The formula to calculate interval:

( $\frac{(n-1).s^{2}}{\chi^{2}_{\alpha/2,n-1}} , \frac{(n-1)s^{2}}{\chi^{2}_{1-\alpha/2,n-1}}$ )

are the lower and upper limits, respectively.

Substituing values:

( $\frac{11.59.29}{21.92} , \frac{11.59.29}{3.816}$ )

(29.7532, 170.9093)

The interval for variance is: 29.7532 ≤ $\sigma^{2}$ ≤ 170.9093

6 0

3 years ago

???????????????????????????????

Taya2010 [7]

You are trying to isolate x, so you would first subtract the y and get ax-bx= z-y
then you would divide by a-b
giving you A as the answer

5 0

3 years ago