Answer:
x = 2000 cameras
Step-by-step explanation:
C(x) Total cost in producing x units
C- = C(x) /x Average cost of producing x units x > 0
Cannon Precision Instrument
C (x) Total monthly cost for producing x units of M1 cameras
is C(x) = 0.0025x² + 80x + 10000
Then average cost of producing x cameras M1 is
C-(x) = ( 0.0025x² + 80x + 10000) /x
C-(x) = 0.0025x + 80 + 10000/x
Taking derivatives on both sides of the equation
C-´(x) = 0.0025 - 10000/x²
Then
C-´(x) = 0
( 0.0025x² - 10000 ) / x² = 0
0.0025x² - 10000 = 0
x² = 10000 /0.0025 x² = 4000000
x = 2000 cameras
Answer:3
Step-by-step explanation:
Hey there! I'm happy to help!
So we want to see which of these have the greatest value. Since these are all negative numbers, we want the one that is closest to zero.
So, we know that -1000 is going to furthest from 0. -10 will be further than -8 since it is a larger negative number, so it will be more negative than -8.
-1/2 is just barely negative, so it is going to be closer to -0 than -8, so the correct answer is C. -1/2.
Have a wonderful day and keep on learning! :D
Answer:
-1, -1
Step-by-step explanation:
The equation you can use is x + 3x = 428 with x as the number of cheeseburgers and 3x the number of hamburgers
you solve for x and get 4x= 428 and x=107
so 321 hamburgers were sold that day.
