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2 years ago

The sum of two numbers is 12 and the quotient of those numbers is -4.

Mathematics

1 answer:

Alisiya [41]2 years ago

4 0

Answer:

16 and -4

Step-by-step explanation:

16 + (-4) = 12

16 / -4 = -4

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Solve the equation. 6x=2x^2+1

7nadin3 [17]

6x = 2x^2 + 1
2x^2 - 6x + 1 = 0
$x= \frac{-(-6) \pm \sqrt{(-6)^2-(4 \times 2 \times 1)}}{2 \times 2}\\=\frac{6\pm\sqrt{36-8}}{4}\\=\frac{6\pm\sqrt{28}}{4}\\=\frac{6\pm2\sqrt{7}}{4}\\=\frac{3\pm\sqrt{7}}{2}\\=\frac{3+\sqrt{7}}{2}\,or\,\frac{3-\sqrt{7}}{2}$

7 0

2 years ago

Find the coefficient of x^4 in the expansion of (1 + 2x + 3x^3)^10?

Lesechka [4]

$(1+2x+3x^3)^{10}$

The only possible configurations of terms that contribute to generating the $x^4$ term in the expansion are given by the multinomial theorem to be

$\left(\dbinom{10}{6,4,0}(1)^6(2x)^4(3x^3)^0+\dbinom{10}{8,1,1}(1)^8(2x)^1(3x^3)^1\right)x^4$

where

$\dbinom{10}{k_1,\ldots,k_m}=\dfrac{10!}{k_1!\cdots k_m!}$

Simplifying a bit gives a coefficient of

$\dbinom{10}{6,4,0}(2)^4+\dbinom{10}{8,1,1}(2)(3)$
$16\dbinom{10}{6,4,0}+6\dbinom{10}{8,1,1}$
$16\dfrac{10!}{6!4!0!}+6\dfrac{10!}{8!1!1!}$
$16(5\times3\times2\times7)+6(10\times9)=3900$

3 0

3 years ago

The cell phone plan from Company C costs $10 per month, plus $15 per gigabyte for data used. The plan from Company D costs $80 p

Eddi Din [679]

Answer:

C(g) = 10 + 15g

C'(g) = 80

The monthly charges of Company C for using 2 Gigabyte of data usage.

Step-by-step explanation:

The cell phone plan from Company C costs $10 per month, plus $15 per gigabyte for data used. The plan from Company D costs $80 per month, with unlimited data.

Now, the monthly cost in Company C for using g gigabyte of data will be

C(g) = 10 + 15g ........ (1)

Again, the monthly cost in Company D for using g gigabyte of data will be

C'(g) = 80 ......... (2)

Now, from equation (1), the statement C(2) = 10 + 15 × 2 = 40, means that monthly charges of Company C for using 2 Gigabyte of data usage. (Answer)

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3 years ago

On Monday, the rover traveled 330 cm. On Tuesday,it traveled 180 cm. If the rover stoped every 15 cm to recharge, how many more

boyakko [2]

10 more times

On Monday the rover needed to charge 22 times and on Tuesday 12 times.
So the answer is 22-12=10

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3 years ago

The dot plot shows the number of magazines sold determine the median of the date set

marta [7]

To find median you set up the number least to greasiest and then cross each one out one side at a time until you get to the middle

8 0

3 years ago